3 years ago

3x + 8 < 4(x - 3)Solve the inequality and graph the solution set.

Mathematics

1 answer:

solmaris [256]3 years ago

7 0

Step-by-step explanation:

3x+8<4x−12

Move all terms containing x

to the left side of the inequality.

Tap for more steps...

−x+8<−12

Move all terms not containing x

−x<−20

x>20

Interval Notation:(20,∞)

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What is the cube root of -729a^9b^6?<br> -9a^3b^2<br> -9a^2b^<br> -8a^3b^2<br> -8a^2b^3

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Answer:

$= 9a^3b^2$

Step-by-step explanation:

$\sqrt[3]{-729a^9b^6} =$

$= ((-9)^3a^9b^6)^{\frac{1}{3}$

$= (-9)^{3 \times \frac{1}{3}} \times a^{9 \times \frac{1}{3}} \times b^{6 \times \frac{1}{3}}$

$= (-9)^{1} \times a^{3} \times b^{2}$

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What is -0.75 - 0.4 simplified

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Answer:

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Read 2 more answers

The midpoint M and one endpoint of JK are given. Find the coordinates of the other endpoint. J(7,2) and M(1,-2)

djverab [1.8K]

Step-by-step explanation:

Xj + Xk/2 = Xm

7 + Xk/2 = 1

to get rid of the bracket, multiply all two sides by the denominator.

2(7 + Xk/2) = 1(2)

7 + Xk = 2

Xk = 2 - 7

Xk = -5

Yj + Yk/2 = Ym

2 + Yk/2 = -2

to get rid of the bracket, multiply all two sides by the denominator.

2(2 + Yk/2) = -2(2)

2 + Yk = -4

Yk = -4 - 2

Yk = -6

Therefore the coordinates of point K is (-5,-6)

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