I think it’s D I’m not sure .........
The rate constant : b. 1/ M² · s
<h3>Further explanation </h3>
The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.
For A + B ---> C + D
Can be formulated:
![\large{\boxed{\boxed{\bold{v~=~k.[A]^a[B]^b}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Bv~%3D~k.%5BA%5D%5Ea%5BB%5D%5Eb%7D%7D%7D)
where
v = reaction speed, M / s
k = constant, mol¹⁻⁽ᵃ⁺ᵇ⁾. L⁽ᵃ⁺ᵇ⁾⁻¹. S⁻¹
a = reaction order to A
b = reaction order to B
[A] = [B] = concentration of substances
Units of the rate constant - k depend on rate law, so it is unique for the specific reaction
So for the rate law :
Δ[C]/ΔT = k[A]²[B] , the units are :
![\tt \dfrac{M}{s}=k\times M^2\times M\\\\k=\dfrac{M/s}{M^2\times M}\\\\k=\dfrac{1}{M^2.s}](https://tex.z-dn.net/?f=%5Ctt%20%5Cdfrac%7BM%7D%7Bs%7D%3Dk%5Ctimes%20M%5E2%5Ctimes%20M%5C%5C%5C%5Ck%3D%5Cdfrac%7BM%2Fs%7D%7BM%5E2%5Ctimes%20M%7D%5C%5C%5C%5Ck%3D%5Cdfrac%7B1%7D%7BM%5E2.s%7D)
Answer:
<em>D. The total amount of energy in the system always stays the same</em>
Explanation:
Answer:
One electron per single hydrogen atom.
Explanation:
Hello!
In this case, given the reaction:
![H_2+O_2\rightarrow H_2O](https://tex.z-dn.net/?f=H_2%2BO_2%5Crightarrow%20H_2O)
Whereas we can identify the following half-reaction for hydrogen:
![H_2^0\rightarrow H_2^+](https://tex.z-dn.net/?f=H_2%5E0%5Crightarrow%20H_2%5E%2B)
Whereas we see that each single hydrogen atom gains one electron in order to go from 0 to +1, which is also related to an oxidation half-reaction.
Best regards!