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3 years ago

14

Ashley has 4 pairs of low-top sneakers, 7 pairs of high-top sneakers, 3 pairs of sandals, and 1 pair of boots. What is the ratio

of the pairs of low-top sneakers to the total number of pairs of shoes

1 answer:

Citrus2011 [14]3 years ago

6 0

The ratio of low-top to the total number of shoes is 4:15

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How do you divide 24,986.73 by 216.06?

REY [17]

249863.73/216.06
=115.6471

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3 years ago

Read 2 more answers

Evaluate ,where e is the solid that lies between the cylinders x^2+y^2=1 and x^2+y^2=16, above the xy-plane, and below the plane

MA_775_DIABLO [31]

Assuming you're just computing the volume, i.e.

$\displaystyle\iiint_E\mathrm dV$

we should convert to cylindrical coordinates first, setting

$\begin{cases}x=r\cos\theta\\y=r\sin\theta\\z=\zeta\end{cases}$

so that the volume is given by

$\displaystyle\iiint_E\mathrm dx\,\mathrm dy\,\mathrm dz=\int_{\theta=0}^{\theta=2\pi}\int_{r=1}^{r=4}\int_{\zeta=0}^{\zeta=r\sin\theta+4}r\,\mathrm d\zeta\,\mathrm dr\,\mathrm d\theta$

which has a value of $60\pi$ .

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3 years ago

An engine cylinder 13.7 cm deep is being bored such that the radius increases by 0.13 mm divided by min. How fast is the volume

zzz [600]

Answer:

Step-by-step explanation:

Given that an engine cylinder 13.7 cm deep is being bored such that the radius increases by 0.13 mm divided by min.

We convert everything in mm for uniformity

We have formula for volume as

$V=\pi r^2 h$

Given that $\frac{dr}{dt} =0.13$

h is constant

$V= 3.14 (r^2) (13.7)\\\frac{dV}{dt} =6.28 (137) r dr/dt\\= 6.28(137)\frac{ (97)}{2} 0.13$

= 6954.67 mm/sec^3

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3 years ago

rewrite the polynomial 2y^2+ 6y^3-11-17y^4+8y^5 in the standard form also find its degree and coefficient of y^4

OleMash [197]

Answer:

The standard form is 8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

The degree of given polynomial is '5'

the co-efficient of y⁴ is '-17'

Step-by-step explanation:

Given standard form 2 y²+ 6 y³-11-17 y⁴+8 y⁵

<em>The form ax² + b x + c is called the standard form of the quadratic expression of 'x'.This is second degree standard form of polynomial.</em>

<em>The form ax⁵ + b x⁴ + c x³ +d x² +ex +f is called the standard form of the quadratic expression of 'x'.This is fifth degree standard form of polynomial</em>

now Given polynomial is 2 y²+ 6 y³-11-17 y⁴+8 y⁵

The standard form is

8 y ⁵ - 17 y⁴ + 6 y³ +2 y² - 11

<u><em>Conclusion</em></u>:-

<em>The degree of given polynomial is '5'</em>

<em>The co-efficient of y⁴ is '-17'</em>

<em> </em>

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3 years ago

Maurice averaged 79 points for 6 tests. How many more points must he score in the next text to raise his average to 80.

Lady bird [3.3K]

Answer:

86 is the score that Maurice must get to average his score to 80

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2 years ago