If AP 10 - 12. what is the perimeter of quadrilateral TAEO (a) 56 (b)64 (c)72 (d)76

Mathematics

1 answer:

BlackZzzverrR [31]2 years ago

4 0

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Someone please helpp

umka2103 [35]

Answer:

The two equations are similar because they both end up with the same common value. 0=0 The work you need to show that this is correct will be shown below.

Step-by-step explanation:

2(5m−4)−3(m−5)2=−3m2+40m−83

Add 3m^2 to both sides.

−3m2+40m−83+3m2=−3m2+40m−83+3m2

40m−83=40m−83

Subtract 40m from both sides.

40m−83−40m=40m−83−40m

−83=−83

−83+83=−83+83

0=0

If you have any questions regarding my answer please tell me in the comments, I will come and answer them. Have a good day.

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Ede4ka [16]

Answer:

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Step-by-step explanation:

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NO LINKS!!!! Find the equation of the circle below

inysia [295]

Answer:

$(x+3)^2+(y-2)^2=9$

Step-by-step explanation:

Equation of a circle

$(x-a)^2+(y-b)^2=r^2$

where:

(a, b) is the center
r is the radius

From inspection of the diagram, the center of the circle appears to be at point (-3, 2), although this is not very clear. Therefore, a = -3 and b = 2.

Substitute these values into the general form of the equation of a circle:

$\implies (x-(-3))^2+(y-2)^2=r^2$

$\implies (x+3)^2+(y-2)^2=r^2$

Again, from inspection of the diagram, the maximum vertical point of the circle appears to be at y = 5. Therefore, to calculate the radius, subtract the y-value of the center point from the y-value of the maximum vertical point:

⇒ radius (r) = 5 - 2 = 3

Substitute the found value of r into the equation:

$\implies (x+3)^2+(y-2)^2=3^2$