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ikadub [295]
3 years ago
11

Which is the best example of forces acting in the same direction?

Mathematics
2 answers:
marusya05 [52]3 years ago
8 0

Answer: The answer is two football players pushing a tackling sled because obviously they are going in the same direction. So yeah your answer is B 100% sure!

attashe74 [19]3 years ago
8 0

Answer:

The Correct answer is <em>B) two football players pushing a tackling sled</em>

Step-by-step explanation:

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Can someone help me please
Novosadov [1.4K]

Answer:

Substitute the 80°F where the F is in the equation. then just put the whole equation into your calculator. I got approximately 26.7.

4 0
3 years ago
There are 9321 leaves on a tree explain why the digit 3 stay the same when
Nat2105 [25]

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

                  Hello!

✧・゚: *✧・゚:*    *:・゚✧*:・゚✧

❖ The 3 remains the same when 9,321 is rounded because if you look to the right of the number in the hundreds place, you see 2. 5 and above, give it a shove (round up). 4 and below, leave it alone (round down). Since 2 is below 5, we leave it alone. So 9,321 is rounded to 9,300.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

6 0
3 years ago
Read 2 more answers
A picture frame is shaped like a rectangle whose perimeter is 196 cm. The length is 6 times long as the width
lbvjy [14]
L=length W=width
perimeter=2Lx2W
196=2L+2W

Length can be written as 6W because it is 6 times the width. We then substitute this in so all the terms are the same

196=2(6W)+2W
196=12W+2W
196=14W
W=14cm
L= (14x6) 84cm
3 0
3 years ago
Find the area of the parallelogram
iogann1982 [59]

Answer:

The answer is 32.

Step-by-step explanation:

Just multiply the height by the base length. 4*8=32

8 0
3 years ago
How many times must we toss a coin to ensure that a 0.95-confidence interval for the probability of heads on a single toss has l
musickatia [10]

Answer:

(1) 97

(2) 385

(3) 9604

Step-by-step explanation:

The (1 - <em>α</em>) % confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The margin of error in this interval is:

MOE= z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

The formula to compute the sample size is:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}

(1)

Given:

\hat p = 0.50\\MOE=0.1\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.1^{2}}\\=96.04\\\approx97

Thus, the minimum sample size required is 97.

(2)

Given:

\hat p = 0.50\\MOE=0.05\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.05^{2}}\\=384.16\\\approx385

Thus, the minimum sample size required is 385.

(3)

Given:

\hat p = 0.50\\MOE=0.01\\z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

*Use the <em>z</em>-table for the critical value.

Compute the value of <em>n</em> as follows:

\\n=\frac{z_{\alpha/2}^{2}\times \hat p(1-\hat p)}{MOE^{2}}\\=\frac{1.96^{2}\times0.50\times(1-0.50)}{0.01^{2}}\\=9604

Thus, the minimum sample size required is 9604.

8 0
3 years ago
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