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Snezhnost [94]
2 years ago
10

Frameshift mutation are the result of what occurrence?​

Biology
1 answer:
Alisiya [41]2 years ago
7 0

Explanation:

A frameshift mutation (also called a framing error or a reading frame shift) is a genetic mutation caused by indels (insertions or deletions) of a number of nucleotides in a DNA sequence that is not divisible by three. Due to the triplet nature of gene expression by codons, the insertion or deletion can change the reading frame (the grouping of the codons), resulting in a completely different translation from the original. The earlier in the sequence the deletion or insertion occurs, the more altered the protein. A frameshift mutation is not the same as a single-nucleotide polymorphism in which a nucleotide is replaced, rather than inserted or deleted. A frameshift mutation will in general cause the reading of the codons after the mutation to code for different amino acids. The frameshift mutation will also alter the first stop codon ("UAA", "UGA" or "UAG") encountered in the sequence. The polypeptide being created could be abnormally short or abnormally long, and will most likely not be functional.

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A gene has 2 alleles, R & B, List the possible genotypes? I also need help with questions 5, 6, 7 and 8 please help! Pls loo
irakobra [83]

Answer:

5.) The possible genotypes should be: RR RB BB ( if the could for the same proteins)

6.) Frequency of R: 0.5

7.)Frequency of R: 0.5

8.)Frequency of R: 0.375

Explanation:

5.) If R and B code for the different forms of the same protein then they are only a few possible out comes

6.) First calculate the total alleles in population

allele R= 40

Allele B=40

total allele = R+B= 40+40

=80

Now to find allele R frequency is:

(Total R alleles) / (Total allele in pop)

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0.5

7.)Calculate the total alleles

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R=10x 2= 20

Multiply the value by 2 because there are 2 R alleles present in

RB=20

R=20

Number doesn't change there is only 1 R allele

Total R=20+20

=40

Alleles For B

BB=10

B=10×2

=20

Same thing here, two B alleles together so multiple by 2

RB=20

B=20

Total B= 20+20

=40

Total alleles in pop add

40+40

=80

Frequency of R

Total of R/Total Alleles

=40/80

=0.5

8.)Repeat the same thing in 7 but use different numbers

RR=10

R=10x2

=20

RB=10

R=10

Total R= 20+10

=30

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_______________________________________
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