Answer: 25 yards
Explanation:
Your radius is half the diameter
9514 1404 393
Answer:
A. 40.7%
Step-by-step explanation:
The selling price for a $5 profit will be ...
$12.75 +5.00 = $17.75
From $29.95, this represents a change of ...
(17.75 -29.95)/29.95 × 100%
= -12.20/29.95 × 100% ≈ -40.7346%
The bookstore can offer a maximum discount of about 40.7%.
Answer:
All numbers can be written as a product of the prime numbers that conform them.
A) Find two numbers with a common factor of 3 only.
for example:
2*3 = 6
7*3 = 21
Both numbers have the factor 3 in them, and because the other two numbers are primes, we can be sure that the 3 is the only common factor.
B) Write a pair of numbers with a common factor of 2, 3 and 6.
Here we can write:
2*3*2 = 12
3*2*5 = 30
Those two numbers have the common factors 6, 2 and 3.
C) Write a pair of numbers with common factors of 3, 6 and 9.
3*2*3 = 18 (has the factors 2, 3, 3*2 = 6, 3*3 = 9)
-3*2*6 = -36
Both have the common factors 3, 6 and 9 (and they share more common factors like 2, this happens because 6 = 3*2, so if 6 is a common factor, 2 also must be)
75+ 15x ≥ 140
⇒ 15x ≥ 140-75
⇒ 15x ≥ 65
⇒ x ≥ 65/15
⇒ x ≥ 13/3
⇒ x ≥ 4 1/3
Final answer: x ≥ 4 1/3~
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140
has a pvalue of 0.9772
X = 125
has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
