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Lera25 [3.4K]
3 years ago
6

Jenna has a bag that contains 7 red marbles and 25 blue marbles. She selects a marble at random, and then, without replacing the

first one, selects another marble at random.
What is the probability that Jenna selects a blue marble and then a red marble? Round your answer to the nearest percent.

P(blue and red) ≈ %
Mathematics
1 answer:
Kisachek [45]3 years ago
4 0
Jenna has a bag that contains 7 red marbles and 25 blue marbles.
She selects a marble at random, and then, without replacing the first one, selects <span>another marble at random.
</span>Let's find out the probability that Jenna selects a blue marble and then a red marble?
=> blue marble probability = 1/32 
=> red marble = 1/31
Round to the nearest percentage = 3%

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Two sides of an isosceles triangle measures 26 and 10. What is the possible value of the third side?
spin [16.1K]

The third side of the triangle is 26.

Explanation:  

Given:

Two sides of the isosceles  triangle are 26 and 10.  

To Find:

The possible value of the third side

Solution:

Definition of Isosceles  triangle:

An isosceles triangle is a triangle with (at least) two equal sides. Isosceles triangle  has both two equal sides and two equal angles.

We also know the property of the triangle that  

Sum of two sides of triangle > third side of the triangle  

Case1. When third side is 10

Thee third side can’t be equal to 10 because it does not follow the rule of triangle  

10+10>26………which is  not possible

So the third side of the isosceles triangle is 26.

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What do I do to solve this
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3 0
2 years ago
A party tent is used for an outdoor event. Ropes of equal length support each tent pole. The angle the rope makes with the floor
Virty [35]
Law of sines can be used to solve this problem:

(note - let x represent the missing side length.)

1. set up proportion.
sin 90°/25 = sin 55<span>°/x

2. solve.
(x) sin 90</span>° = (25) sin 55<span>°

(x) sin 90 </span>°/sin 90° = (25) sin 55° / sin 90<span>°
</span>
x = 20.4788011072
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8 0
3 years ago
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mrs_skeptik [129]

Answer:

Step-by-step explanation:

<u>Pool:</u>

Width = x ft

Length = (x+6) ft

<u>Pool along with walkway:</u>

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Length = x + 6 + 5 + 5 = (x + 16) ft

Total area of the pool with walkway = 950 sq.ft

length * width = 950

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Use FOIL method,

x*x + x *10 + 16*x + 16 *10 = 950

x² + 10x + 16x + 160 -950 = 0   {Add like terms}

x² + 26x - 790 = 0

6 0
3 years ago
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