Answer:
1. Sine θ = 1/3
2. Cos θ = 2√2 / 3
3. Tan θ = √2 / 4
4. Cosec θ = 3
5. Sec θ = 3√2 / 4
6. Cot θ = 2√2
Step-by-step explanation:
We'll begin by determining the adjacent. This can be obtained as follow:
Hypothenus (Hypo) = 9
Opposite (Opp) = 3
Adjacent (Adj) =?
Hypo² = Adj² + Opp²
9² = Adj² + 3²
81 = Adj² + 9
81 – 9 = Adj²
72 = Adj²
Take the square root of both side
Adj = √72
Adj = 6√2
Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:
1. Determination of Sine θ
Hypothenus = 9
Opposite = 3
Sine θ =?
Sine θ = Opposite / Hypothenus
Sine θ = 3/9
Sine θ = 1/3
2. Determination of Cos θ
Adjacent = 6√2
Hypothenus = 9
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = 6√2 / 9
Cos θ = 2√2 / 3
3. Determination of Tan θ
Opposite = 3
Adjacent = 6√2
Tan θ =?
Tan θ = Opposite / Adjacent
Tan θ = 3 / 6√2
Tan θ = 1 / 2√2
Rationalise
(1 / 2√2) × (2√2 /2√2)
= 2√2 / 4×2
Tan θ = √2 / 4
4. Determination of Cosec θ
Sine θ = 1/3
Cosec θ =?
Cosec θ = 1 / Sine θ
Cosec θ = 1 ÷ 1/3
Cosec θ = 1 × 3/1
Cosec θ = 3
5. Determination of sec θ
Cos θ = 2√2 / 3
Sec θ =?
Sec θ = 1 / Cos θ
Sec θ = 1 ÷ 2√2 / 3
Sec θ = 1 × 3 / 2√2
Sec θ = 3 / 2√2
Rationalise
= (3 / 2√2) × (2√2 / 2√2)
= 3 × 2√2 / 4×2
Sec θ = 3√2 / 4
6. Determination of Cot θ
Tan θ = √2 / 4
Cot θ =?
Cot θ = 1 / Tan θ
Cot θ = 1 ÷ √2 / 4
Cot θ = 1 × 4 / √2
Cot θ = 4 / √2
Rationalise
= (4 / √2) × (√2 / √2)
= 4√2 / 2
Cot θ = 2√2
Answer:
-21°
Step-by-step explanation:
the temperature was -14 degrees and then dropped by 7 degrees which meant that it became -21 degrees because -14 - 7 = -21
Exponents first, then multiply (PEMDAS)
5•5•5= 125
3•3•3= 27
27•125= 3375
all of them are the correct answer
