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Aliun [14]
2 years ago
10

The length of bamboo grows much faster than that of thickness why?​

Biology
1 answer:
iren [92.7K]2 years ago
3 0

Using a slow- and fast-growing variant of bamboo, Wei and colleagues looked at cell division, growth, and gene expression (through transcriptomics, which measures all the genes being expressed by an individual) to discover which genes may be responsible for fast growth in bamboo. They found that the slow-growing variant had reduced expression of genes relating to cell wall construction, the plant hormone auxin (important for cell growth and cell division), and had irregular cell growth and cell walls. Wei and colleagues suggest that a reduced ability to produce and perceive auxin, combined with a weakened cell wall, are responsible for the slow growth seen in the bamboo variant.

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One g of fecal matter was suspended in 99 ml saline solution (tube 1). After mixing gently but thoroughly, one ml from tube 1 wa
malfutka [58]

Answer: the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3

Explanation:

We know that; Gram negative bacteria looks  pale reddish in color under a light microscope from Gram staining.

therefore

There are 30 red bacterial colonies counted.

1 mL of from tube 1 was removed and added to tube with 99 mL saline (tube 2) dilution is 1/100.

transferred volume  into the plate is 1 mL.

Now, we have to determine the cfu/g Gram-negative bacteria in the fecal sample

Formula to calculate CFU/g bacteria in fecal sample is expressed as;

C = n/(s×d )

where C is concentration (CFU/g) , n is number of colonies , s is volume transferred to plate , d is dilution factor.

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THERFERE, the cfu/g Gram-negative bacteria in the fecal sample is C = 3.0 × 10^3

3 0
3 years ago
Imagine you are a geneticist interested in studying a newly discovered species of very colorful birds. You have found that a sin
kolbaska11 [484]

The frequency <em>p</em> of the yellow (A) allele is  <em>p</em>= 0.3

The frequency <em>q</em> of the blue (a) allele is  <em>q= </em><em>0.7</em>

Hardy–Weinberg equilibrium,  states that allele and genotype frequencies in a population will remain constant from generation to generation. Equilibrium is reached in the absence of selection, mutation, genetic drift and other forces and allele frequencies p and q are constant between generations. In the simplest case of a single locus with two alleles denoted A and a with frequencies f(A) = p and f(a) = q, the expected genotype frequencies under random mating are f(AA) = p² for the AA homozygotes, f(aa) = q² for the aa homozygotes, and f(Aa) = 2pq for the heterozygotes.  

p²+2*p*q+q²= 1       p+q= 1     q= 1-p

yellow (p²)= 9%= 0.09               p= √0.09= 0.3

green (2*p*q)= 42%= 0.42        

blue (q²)=49%= 0.49                q=1-0.3= 0.7 <em>or</em> q= √0.49= 0.7


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