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RideAnS [48]
3 years ago
5

Please help part 1 part 3 and 3

Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

no

Step-by-step explanation:

x²-2x-5=0

a=1

b=-2

c=-5

So also you need to correct the equasion according to the schematic below:

x=(-b+-root(b²-4*a*c))/2*a

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Based on the graphs of f (x) and g(x), what must the domain of (f ⋅ g)(x) be?
bekas [8.4K]

Using the concept of domain, the domain of (f.g)(x) is given by:

{x ∈ ℝ | x ≠ 3}

---------------------

  • The domain of a function is given by all possible input values, that is, <u>on a graph, all values that the x-axis assumes.</u>
  • In the graph, <u>function f assumes all real values.</u>
  • Function g is not defined for x = 3, thus, it's domain is all real values except 3.
  • Thus, the multiplication, as fg(x) = f(x) \times g(x), will also not be defined at x = 3, and the domain of the multiplication is:

{x ∈ ℝ | x ≠ 3}

A similar problem is given at brainly.com/question/4175434

4 0
3 years ago
I need help with this! Quick ASAP?
sp2606 [1]

Answer:

a) F

b) B, E, D

Step-by-step explanation:

a) The segment with the greatest gradient has the largest change in y-values per unit change in x-values

From the given option, the rate of change of the <em>y </em>to the<em> </em>x-values of B = the gradient = (4 units)/(2 units) = 2

The gradient of F = (-3units)/(1 unit) = -3

The gradient of A = 4/4 = 1

The gradient of C = -2/5

The gradient of D = 2/6 = 1/3

The gradient of E = 3/4

The segment with the greatest gradient is F

b) The steepest segment has the higher gradient

From their calculated we have;

The gradient of segment B = 2 therefore, B is steeper than E that has a gradient of 3/4, and E is steeper than D, as the gradient of D = 1/3

Therefore, we have;

B, E, D.

6 0
3 years ago
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5 0
2 years ago
Graph the function.<br><br> y=1+0.5x
Contact [7]

Good evening ,

___________________________________________________________

To graph such function we need only 2 points that their coordinates verify the equation y=1+0.5x then we link them with a line.

Look at the photo below for the graph.

:)

5 0
4 years ago
At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

dy/dx = 2

Using the relation;

m1m2 = -1

m2 = -1/2

Hence;

y = 1/4 - 5(-1/2)

y = 1/4 + 5/2

y = 7/2

Thus the points are; (7/2, -1/2)

Learn more about normal curve:brainly.com/question/10664419

#SPJ4

7 0
2 years ago
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