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Leona [35]
3 years ago
5

A study of telephones and the risk of brain cancer looked at a group of 469 people who have brain cancer. The investigators matc

hed each cancer patient with a person of the same sex, age and race who didn’t have brain cancer, then asked about use of cell phones. This is
a) observational study
b)A matched pair experiment
c)An uncontrolled experiment
d)A randomized comparative study
Mathematics
1 answer:
Svetlanka [38]3 years ago
8 0
This is an A. <span>observational study. They are observing the use of cell phones differs between people with or without cancer.

Happy studying ^-^</span>
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Find the value for x in the rectangular prism. Use exact values. ​
Svetlanka [38]

Answer:

x = 2\sqrt{66}

Step-by-step explanation:

x = \sqrt{2^2+8^2+14^2}

  = \sqrt{4+64+196}

  = \sqrt{264}

  = 2\sqrt{66}

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If an additional dot is added to the set in the 3 column, how will the mean change? What will the new mean be?
Westkost [7]

Answer:

I do not understand the question

Step-by-step explanation:

I do not understand the question. Perhaps you can add a picture to clearify?

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3 years ago
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Find an angle in each quadrant with a common reference angle with 77°, from 0°≤θ&lt;360°
mr Goodwill [35]

Answer:

Q1: 77°, Q2: 103°, Q3: 257°, Q4: 283°

Step-by-step explanation:

Note: Q1 = Quadrant 1

Q1: 77°

Q2: 180° - 77° = 103°

Q3: 180° + 77° = 257°

Q4: 360° - 77° = 283°

8 0
3 years ago
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A random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used. A survey of 500 randomly selecte
vodka [1.7K]

Answer:

We conclude that the mean Ohio score is below the national average.

Step-by-step explanation:

We are given that a random survey of 1000 students nationwide showed a mean ACT score of 21.1. Ohio was not used.

A survey of 500 randomly selected Ohio scores showed a mean of 20.8. The population standard deviation is 3.

<u><em>Let </em></u>\mu<u><em> = mean Ohio scores.</em></u>

So, Null Hypothesis, H_0 : \mu \geq 21.1      {means that the mean Ohio score is above or equal the national average}

Alternate Hypothesis, H_A : \mu < 21.1      {means that the mean Ohio score is below the national average}

The test statistics that would be used here <u>One-sample z test statistics</u> as we know about population standard deviation;

                    T.S. =  \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n}}}  ~ N(0,1)

where, \bar X = sample mean Ohio score = 20.8

            \sigma = population standard deviation = 3

            n = sample of Ohio = 500

So, <u><em>test statistics</em></u>  =  \frac{20.8-21.1}{\frac{3}{\sqrt{500}}}  

                              =  -2.24

The value of z test statistics is -2.24.

<em>Now, at 0.1 significance level the z table gives critical value of -1.2816 for left-tailed test.</em><em> Since our test statistics is less than the critical values of z as -2.24 < 1.2816, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which </em><em><u>we reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the mean Ohio score is below the national average.

4 0
3 years ago
What is 2 3/4 - 5/16​
Ilya [14]

Answer:

2 7/16

Step-by-step explanation:

multiply both top and bottom of 2 3/4 to make it 12/16 then subtract from there.

6 0
3 years ago
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