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Ilia_Sergeevich [38]
3 years ago
12

Which statement is true?

Mathematics
2 answers:
V125BC [204]3 years ago
7 0
We know, The numbers on a Horizontal number line are Oriented from left to right and Bottom to Top on a Vertical number line.

In short, Your Answer would be: Option C

Hope this helps!
erica [24]3 years ago
4 0
The answer to your question is C
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Just wondering is 71 a PRIME number? ≡≡≡
Sergeu [11.5K]
Yes 71 is a Prime Number
7 0
3 years ago
Read 2 more answers
1)A System of equations is shown below . What is the solution to the system of equations? 5x+2y=-15 2x-2y=-6
meriva

Answer:

x= -3 and y= 0

Step-by-step explanation:

5x+2y=-15

<u>2x-2y=-6     </u>

<u>7x        =-21</u>

x= -3

Putting value of x in equation 1  

5(-3) +2y=-15

-15+2y= -15

2y= 0

y= 0

This can be solved with the help of matrices

In matrix form the above equations can be written in the form

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right]  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

Let

\left[\begin{array}{ccc}5&2\\2&-2\/\end{array}\right] = A  \left[\begin{array}{ccc}x\\y\\\end{array}\right]  = X  and  \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]= B

Then AX= B

or X= A⁻¹ B

where  A⁻¹= adj A/ ║A║   where mod A≠ 0

adj A=  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]

║A║= ( 5*-2- 2*2)= -10-4= -14≠0

X= A⁻¹ B

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14  \left[\begin{array}{ccc}-2&-2\\-2&5\/\end{array}\right]   \left[\begin{array}{ccc}-15\\-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]    =- 1/14     \left[\begin{array}{ccc}-2*-15&+ -2*-6\\-2*-15&+ 5*-6\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc} 30&+12\\30&+-30\\\end{array}\right]

 \left[\begin{array}{ccc}x\\y\\\end{array}\right]  =- 1/14 \left[\begin{array}{ccc}42\\0\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-42/14\\0/-14\\\end{array}\right]

\left[\begin{array}{ccc}x\\y\\\end{array}\right]  = \left[\begin{array}{ccc}-3\\0\\\end{array}\right]

From here x= -3 and y= 0

Solution Set = [(-3,0)]

3 0
3 years ago
hello! i struggle with math A LOT so if u guys can help me with these questions with the work i would appreciate a lot
elena-s [515]
Pretty sure 1 is 6/8
4 0
3 years ago
Read 2 more answers
Lucy has one and one fourth cup of sugar in a cookie recipe calls for 2/3 cup of sugar how many cups of sugar will she have left
cluponka [151]

Answer:

\frac{7}{12}

Step-by-step explanation:

1 \frac{1}{4}  -  \frac{2}{3}  = \frac{5}{4}  -  \frac{2}{3}  =  \frac{15 - 8}{12} =  \frac{7}{12}

5 0
3 years ago
4 &gt; p - 1
alexdok [17]

Answer:

p < 5

I think this is the answer?..

5 0
2 years ago
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