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torisob [31]
2 years ago
14

How do you solve this?

Mathematics
1 answer:
navik [9.2K]2 years ago
7 0

Answer:

62

Step-by-step explanation:

Since you know that JK + KL = JL, this would be:

27 + 3x - 1 = 5x + 2

Now, solve this equation:

combine like terms first

26+3x=5x+2

subtract 3x from both sides

26 = 2x+2

subtract 2 from both sides

24 = 2x

divide both sides by 2

12 = x, x= 12

Since you want to find JL and JL = 5x + 2, plug x = 12 into that equation.

JL = 5* 12 + 2\\JL = 60 + 2\\JL = 62

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30 IS 12% OF 250

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3 years ago
Among all pairs of numbers whose difference is 20, find a pair whose product is as small as possible. what is the minimum produc
Elza [17]

Answer:

-100

-10, 10

Step-by-step explanation:

Let the smaller number be x.

Then the larger number is x + 20.

The product is x(x + 20).

Now you can write the function

y = x(x + 20)

y = x^2 + 20x

Take the first derivative of y with respect to x.

y' = 2x + 20

Set the first derivative equal to zero to find the x value for the minimum value of the function.

2x + 20 = 0

2x = -20

x = -10

The minimum value of the function occurs at x = -10. -10 is one of the two numbers.

y = x^2 + 20x

For x = -10,

y = (-10)^2 + 20(-10)

y = 100 - 200

y = -100

The minimum value of the product is -100.

x = -10

x + 20 = -10 + 20 = 10

The numbers are -10 and 10.

If you have not learned derivatives yet, then plot the function

y = x^2 + 20x

Now look at the graph and find the minimum y value and the x value at which it occurs.

The minimum y value is -100. That is the minimum product you are looking for.

The x value of the minimum function value is x = -10.

Then x + 20 = -10 + 20 = 10.

The numbers are -10 and 10.

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