The answer would be the third one, all you are doing is substituting a value of 1 when you see an x in the function
Step-by-step explanation:
(5y+6)^2=24
i.e, 25y^2+60y+36=24
i.e, 25y^2+60y+12=0
i.e, using rule of quadratic equns
y= {-60±√3600-(4×25×12)}/2×25
i.e,y= (-60±√2400)/50
i.e,y= -1.2 ± 0.4√6
✌️:)
The ending time would be 3:01 p.m. You simply add 15 to 246 and configure it into the way a clock tells time!
Answer:
857.766cm^3
Step-by-step explanation:
Given data
Lenght = 3m
Internal radius r = 3m
External radius R= 10m
Volume of pipe= πr^2h
Volume of metal= External - Internal
Volume= πR^2h-πr^2h
Volume= πh(R^2-r^2)
Volume= 3.142*3(10^2-3^2)
Volume= 3.142*3(100-9)
Volume= 9.426*(91)
Volume= 857.766cm^3
Hence the volume of the metal is 857.766cm^3
Y=x^2
y=1/3(x+4)^2-9
Hope this helps
