PLEASE HELP ME ! im timed !

I need help with the equation (11) - 2.

nirvana33 [79]

Answer:

it's technically 9 because it's the same as 11-2

3 0

3 years ago

Write the equation of the line containing the points (3, 6) and (7, - 2) in standard form.

Rama09 [41]

Answer:

$y = mx + c \\ 6 = 3m + c...(1) \\ - 2 = 7m + c...(2) \\ subtract \: (2) - (1) \\ 4m = - 8 \\ \therefore \: m = - 2 \: sub \: in \: (1) \\ 6 = 3( - 2) + c \\ \therefore \: c = 12 \\ \boxed{y = - 2x + 12}$

7 0

2 years ago

Read 2 more answers

Find the surface area of a square pyramid with side length 4 mi and slant height 5 mi.

andriy [413]

Answer:

SA = 56 sq mi

Step-by-step explanation:

SA = area of base + 1/2(perimeter of base)(slant height)

SA = 16 + 1/2(16)(5)

SA = 16 + 8(5)

SA = 16 + 40

3 0

2 years ago

Identify the value of x that makes each pair of ratios equivalent.

AveGali [126]

Answer:

a.3

Step-by-step explanation:

2:x and 12:18

We need to get from 2 to 12 and 3 to 18

2* something = 12 x* something = 18

Divide by 2

something =12/2

something =6

x*6 = 18

x = 18/6

x=3

3 0

3 years ago

Please for the love of god anwser my question lay correctly I really need your help :( I will give 25 points :)! This is geometr

tangare [24]

Answer:

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

Step-by-step explanation:

we have a square and a triangle

we want to figure out the area and the perimeter of the pentagon

to figure out the area of the pentagon we can use the given formula:

$\displaystyle \rm A_{ \text{c - pentagon}} = A_{ \text{squre}} - A_{ \text{triangle}}$

let's figure out $A_{\rm square}$ :

since the given shape is a square Every angle of its 90° Thus the triangle is a right angle triangle

therefore the height is 4

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times b \times h$

substitute h and b

$\displaystyle A _{ \rm triangle} = \frac{1}{2} \times 4 \times 4$

reduce fraction:

$\displaystyle A _{ \rm triangle} = 2 \times 4$

simplify multiplication:

$\displaystyle A _{ \rm triangle} = 8$

likewise square

$\displaystyle A _{ \rm squre} = {s}^{2}$

substitute s:

$\displaystyle A _{ \rm squre} = {7}^{2}$

simplify square

$\displaystyle A _{ \rm squre} = 49$

hence,

$\displaystyle \rm A_{ \text{c - pentagon}} =49- 8$

$\displaystyle \rm A_{ \text{c - pentagon}} =41$

to figure out perimeter

let's figure out hypotenuse first

$\displaystyle h = \sqrt{ {4}^{2} + {4}^{2} }$

$\displaystyle h = \sqrt{ 16 + 16}$

$\displaystyle h = 4 \sqrt{2}$

therefore,

$\rm \displaystyle P _{ \rm c - pentagon} = 3 + 3 + 4 \sqrt{2} + 7 + 7$

$\rm \displaystyle P _{ \rm c - pentagon} = 6 + 4 \sqrt{2} + 14$

$\rm \displaystyle P _{ \rm c - pentagon} = 20+ 4 \sqrt{2}$

5 0

2 years ago