Fill in each slot in the square with variables <em>a</em>, <em>b</em>, <em>c</em>, <em>d</em>, and <em>e</em>, in order from left-to-right, top-to-bottom. In a magic square, the sums across rows, columns, and diagonals all add up to the same number called the <em>magic sum</em>.
The magic sum is -3.9, since "diagonal 2" (bottom left to top right) has all the information we need:
3 + (-1.3) + (-5.6) = -3.9
Use this to find the remaining elements
<em>a</em> + <em>b</em> + (-5.6) = -3.9
<em>c</em> + (-1.3) + <em>d</em> = -3.9
3 + <em>e</em> + 0.02 = -3.9
<em>a</em> + <em>c</em> + 3 = -3.9
<em>b</em> + (-1.3) + <em>e</em> = -3.9
(-5.6) + <em>d</em> + 0.02 = -3.9
- diagonal 1 (top left to bottom right):
<em>a</em> + (-1.3) + 0.02 = -3.9
You will find
<em>a</em> = -2.62
<em>b</em> = 4.32
<em>c</em> = -4.28
<em>d</em> = 1.68
<em>e</em> = -6.92
Ans
184 sq meter
Step-by-step explanation:
Area of the cuboid box = (2*FA)+(2*SA)+(2*TA)
Where FA= Front face area
SA= Side face area
TA= top face are
Here FA= length * breadth = 10*6=60 sq meter
SA= 10*2= 20 sq meter
TA= 6*2= 12 sq meter
So area of box= 2*60+2*20+2*12= 184 sq meter
2 and a half cups of chocolate I think
Given:
Expression is
To prove:
If r is any rational number, then is rational.
Step-by-step explanation:
Property 1: Every integer is a rational number. It is Theorem 4.3.1.
Property 2: The sum of any two rational numbers is rational. It is Theorem 4.3.2.
Property 3: The product of any two rational numbers is rational. It is Exercise 15 in Section 4.3.
Let r be any rational number.
We have,
It can be written as
Now,
3, -2 and 4 are rational numbers by property 1.
is rational by Property 3.
are rational by Property 3.
is rational by property 2.
So, is rational.
Hence proved.
Answer:
7+28=35
Step-by-step explanation:
