Y = e^tanx - 2
To find at which point it crosses x axis we state that y= 0
e^tanx - 2 = 0
e^tanx = 2
tanx = ln 2
tanx = 0.69314
x = 0.6061
to find slope at that point first we need to find first derivative of funtion y.
y' = (e^tanx)*1/cos^2(x)
now we express x = 0.6061 in y' and we get:
y' = k = 2,9599
The picture in the attached figure
we know that
area of the <span>the shaded region=area of rectangle -area of a kite
area of rectangle=(3x+x)*(x+x)----> 4x*2x---> 8x</span>²
area of a kite=(1/2)*[d1*d2]
where d1 and d2 are the diagonals
d1=4x
d2=2x
so
area of a kite=(1/2)*[4x*2x]----> 4x²
area of the the shaded region=8x²-4x²-----> 4x²
the answer is 4x²
Answer:
Manish has Rs630 while Jhanavi has Rs168.
Step-by-step explanation:
The fraction Manish would have left would be subtracting the fraction on savings as well as that spent on the mall. Which would be;
1 -( 1/2 + 1/4)=1 -3/4 = 1/4
Meaning Manish had 1/4 of his allowance left on him.
Which means 1/4 × Rs. 2520=Rs630
Similarly for Jhanavi, we have :
The fraction left as
1-(1/3 +3/5) = 1 - ( 14/15) = 1/15
Meaning 1/15 of the allowance got remains which is;
1/15 × Rs. 2520= Rs.168
To create a line that is perpendicular to the one given, completely invert the slope.
y = -3/2x + 9
Answer:
It actually gave you the answer.
Step-by-step explanation:
If you read closer, it's telling you the answer. It's giving you examples of radicals and such.