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gtnhenbr [62]
2 years ago
10

Can anyone do this i need it rn+ tell me the part when u answer

Mathematics
1 answer:
Tema [17]2 years ago
6 0

Answer:

Step-by-step explanation:

The first questions are answered on the attachment.

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What is the distance covered by a train while slowing down from
alukav5142 [94]

Answer:

The distance covered is 113.75 m

Step-by-step explanation:

As per the question:

The initial velocity of the train, v = 20 m/s

The final velocity of the train, v' = 6 m/s

Uniform deceleration, a = 1.6m/s^{2}

Or uniform acceleration, a = - 1.6m/s^{2}

<em>Here, the body decelerates, i.e., slows down at a uniform rate thus we take acceleration with negative sign.</em>

Now, to find the distance covered, s:

Using the eqn of Kinemetics:

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3 years ago
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Read 2 more answers
Prove that: 5^31–5^29 is divisible by 100.
ANEK [815]

Answer:

See explanation

Step-by-step explanation:

Consider the expression

5^{31}-5^{29}

First, factor it:

5^{31}-5^{29}=5^{29}\cdot(5^2-1)=5^{29}\cdot (25-1)=24\cdot 5^{29}

Note that

100=25\cdot 4

Then

5^{31}-5^{29}=24\cdot 5^{29}=6\cdot 4\cdot 25\cdot 5^{27}=6\cdot 100\cdot 5^{27}

This shows that number 100 is a factor of the expression 5^{31}-5^{29} and, therefore, this expression is divisible by 100.

5 0
3 years ago
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