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gtnhenbr [62]
3 years ago
10

Can anyone do this i need it rn+ tell me the part when u answer

Mathematics
1 answer:
Tema [17]3 years ago
6 0

Answer:

Step-by-step explanation:

The first questions are answered on the attachment.

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What’s the Y and X intercepts?<br> 12x + y = 120
Bess [88]

Answer:

Y intercept (0,120), x-intercept (10,0)

Step-by-step explanation:

3 0
3 years ago
1. Which of the following is not a linear equation in one variable?
Lorico [155]

\huge \boxed{\mathbb{QUESTION} \downarrow}

Which of the following is not a linear equation in one variable?

a) 33

b) 33(x+y)

c) 33x

d) 33y

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

  • Option <em><u>b) 33 (x + y)</u></em> is not a linear equation in 1 variable.
  • Here, we can see that there are 2 variables used ⇨ x & y. Hence, even though it's a linear equation, it's not in 1 variable.
  • All the other options are in 1 variable or don't have a variable at all.
5 0
3 years ago
explain step by step how to solve. please point out any similarities in the steps used for each question
Mamont248 [21]
#1
m∠A=180 - 115 - 24 = 41°

By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (21*sin24°)/sin41° = (21*0.4067)/0.656 ≈ 13

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (21*sin115°)/sin41° = (21*0.9063)/0.656 ≈ 29


#2
m∠C=180 - 119 - 27 = 34°

By the law of sines:

b/sinB = a/sinA  ⇒  
b = (a*sinB)/sinA = (13*sin119°)/sin27° = (13*0.8746)/0.454 ≈ 25

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (13*sin34°)/sin27° = (13*0.5592)/0.454 ≈ 16


#3
m∠C=180 - 57 - 37 = 86°

By the law of sines:

c/sinC = a/sinA  ⇒  
c = (a*sinC)/sinA = (11*sin86°)/sin57° = (11*0.9976)/0.8387 ≈ 13.1
6 0
4 years ago
The circle described by the equation <img src="https://tex.z-dn.net/?f=%28x-3%29%5E%7B2%7D%20%2B%28y%2B4%29%5E%7B2%7D%3D9" id="T
ElenaW [278]

Answer:

The point at which center of the image circle located is (-2, -3) so second option is correct.

Step-by-step explanation:

Given equation of circle is:

(x-3)^{2} + (y+4)^{2} = 9 (i)

The general equation of circle is mentioned below,

(x-h)^{2} + (y-k)^{2} = r^{2} (ii)

Here 'r' represents the radius of the circle and (h,k) shown the center of the circle.

By comparing equation (i) and equation (ii), we get

r^2 = 9

r = 3

(x-3)^{2} = (x-h)^{2}

(x-3) = (x-h)

h = 3

(y+4)^{2} = (y-k)^{2}

(y+4) = (y-k)

k = -4

So the center of given circle is (h,k) = (3,-4)

Also, the circle is translated 5 units left, that is towards the -x-axis. Therefore h = 3 - 5 = -2

Also, the circle is translated 1 unit up, that is towards the +y-axis. Therefore k = -4 + 1 = -3

Hence, the point at which center of the image circle located is (-2, -3) so second option is correct.

6 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=4%5Csqrt%7B3%7D%2B%5Csqrt%7B3%7D" id="TexFormula1" title="4\sqrt{3}+\sqrt{3}" alt="4\sqrt{3}+\
Firlakuza [10]

Answer:

it's 5\sqrt{3}[/tex]

Step-by-step explanation:

hope it helps you

5 0
3 years ago
Read 2 more answers
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