The area needed is at least 170.5 ft².
Let w = the width of the rectangular area.
Because the length is 15.5 ft, therefore the calculated area should be at least 170.5 ft². That is
(15.5 ft)*(w ft) ≥ 170.5 ft²
w ≥ 170.5/15.5
w ≥ 11 ft
Answer: w ≥ 11 ft
Volume = (l * w * h) or (11 * 3 * x) which will equal surface area. Volume is 33x for now
Surface Area = 2 (x * 11) + 2 (x * 3) + 2 (11 * 3)
Set Volume equal to surface area. I simplified SA already.
33x = 22x + 6x + 66
33x - 28x = 66
5x = 66
x = 66/5 or 13.2
Answer: g(h(3)) = 59
Step-by-step explanation:
Well if its x^3 I assume it is because you wrote other coefficients before the variable.
2(3) - 2 = 6-2 = 4
So 4 is the x input for h(x)
4^3 -5 = 64-5 = 59
There would be 2034 students competing in 2012.
We can write a simple equation to find this answer. Let X, be the number of students starting in 2012. Then, we multiply by 0.9 and 1.1 to get to 2014. To work backwards, just divide by 1.1, then by 0.9.
2014 / 1.1 / 0.9 = 2034
Yes to both, and for future help, if you find a common denominator(the bottom one) by multiplication and one is higher, boom you have your answer.
