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meriva
3 years ago
8

Describe how to write a decimal with 12 repeating digits as a fraction.

Mathematics
1 answer:
ValentinkaMS [17]3 years ago
7 0

Answer: Here are the basic steps as to write any decimal with any amount of repeating digits as a fraction!

1. Create an equation such that x equals the decimal number.

2. Count the number of decimal places, y. Create a second equation multiplying both sides of the first equation by 10y.

3. Subtract the second equation from the first equation.

4. Solve for x.

5. Reduce the fraction.

Let's use the repeating decimal 0.6... with the digit 6 repeating as our example.

Hint: The six's in bold are repeating.

x = 0.6

10x = 6.6

10x - x = 6.6 - 0.6

9x = 6

x = 6/9 or 2/3

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i need help with the last two. I forgot the formula and wondering if you will help me find which one is and isnt a triangle
Nimfa-mama [501]

Answer:

3. D) 26, 7, 31

4. B) 6, 34, 27

Step-by-step explanation:

Both #3 and #4 use the same strategy: the two shorter sides' sum has to be greater than the longer side.

#3:

2 + 8 is 10, which is less than 13. So A wouldn't form a triangle.

12 + 22 is 34, which is the length of the longer side. So B wouldn't form a triangle either.

14 + 18 is 32, which is less than 40. So C wouldn't form a triangle.

7 + 26 is 33, which is greater than 31. So D would form a triangle.

D. 26, 7, and 31 are the only lengths of the ones shown that form a triangle.

#4:

17 + 18 is 35, which is greater than 19. So A would form a triangle.

11 + 22 is 33, which is greater than 25. So C would also form a triangle.

5 + 18 is 23, which is greater than 20. So D would form a triangle.

6 + 27 is 33, which is less than 34. So B wouldn't form a triangle.

B. 6, 34, and 27 are the only lengths of the ones shown that don't form a triangle.

6 0
3 years ago
12x=3/2 what does x=
xz_007 [3.2K]
<h2>>> Answer </h2>

_________

\:

12x =  \frac{3}{2}

x =  \frac{3}{2}  \times  \frac{1}{12}

x =  \frac{3}{24}

x =  \bold{ \frac{1}{8}}

5 0
3 years ago
Read 2 more answers
7) Una epidemia mató los 3/7 de las vacas de un granero y de las que le quedaron vendió 1/2. Si todavía le quedaron 24 vacas, ¿C
4vir4ik [10]

Answer:

Habían inicialmente 84 vacas. Murieron 36 vacas. 24 vacas fueron vendidas.

Step-by-step explanation:

Sea x la cantidad inicial de vacas. De acuerdo con el enunciado, murieron tres séptimos de la cantidad inicial y la mitad de ese remanente fue vendida, quedando 24 vacas. Matemáticamente, tenemos las siguientes operaciones:

Cantidad inicial de vacas

x = \frac{24}{\left(1-\frac{3}{7} \right)\cdot \left(1-\frac{1}{2} \right)}

x = 84

Habían inicialmente 84 vacas.

Cantidad de vacas muertas

y = \frac{3}{7}\cdot x

y = 36

Murieron 36 vacas.

Cantidad de vacas vendidas

z = \left(1-\frac{3}{7} \right)\cdot \frac{1}{2}\cdot x

z = 24

24 vacas fueron vendidas.

8 0
3 years ago
Pumps A, B, and C operate at their respective constant rates. Pumps A and B, operating simultaneously, can fill a certain tank i
jeka94

Let a,b,c be the time it takes for pumps A, B, and C (respectively) to fill 1 tank. Then

\begin{cases}\dfrac1a+\dfrac1b=\dfrac1{\frac65}=\dfrac56\\\\\dfrac1a+\dfrac1c=\dfrac1{\frac32}=\dfrac23\\\\\dfrac1b+\dfrac1c=\dfrac12\end{cases}

Now,

\left(\dfrac1a+\dfrac1b\right)-\left(\dfrac1a+\dfrac1c\right)=\dfrac56-\dfrac23\implies\dfrac1b-\dfrac1c=\dfrac16

Then

\left(\dfrac1b+\dfrac1c\right)+\left(\dfrac1b-\dfrac1c\right)=\dfrac12+\dfrac16\implies\dfrac2b=\dfrac23\implies b=3

This means

\dfrac1a+\dfrac13=\dfrac56\implies\dfrac1a=\dfrac12\implies a=2

and

\dfrac13+\dfrac1c=\dfrac12\implies\dfrac1c=\dfrac16\implies c=6

Working together, all 3 pumps would operate at a rate of

\dfrac1a+\dfrac1b+\dfrac1c=1

or 1 tank in 1 hour, so the answer is D.

8 0
3 years ago
12x-5y=-20<br> y=x+4<br> Please help me asap it's due Wednesday<br> :(
Ahat [919]

Answer:

Point Form:

(0,4)

Equation Form:

x=0,y=4

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

5 0
3 years ago
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