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Mkey [24]
3 years ago
11

Find the area of polygon​

Mathematics
1 answer:
Mumz [18]3 years ago
7 0

Answer:

87 cm²

Step-by-step explanation:

there is 1 triangle and 1 rectangle in the diagram. so you have to find the area of the both polygons and sum up to find the total area of polygon

area of triangle formula:

\frac{1}{2}  \times base \times height

1) area of triangle AED

base = 12 cm

height = 4.5 cm

area:

\frac{1}{2}  \times 12 \times 4.5 = 27 {cm}^{2}

area of rectangle formula:

length \times height

2) area of rectangle ABCD

length = 12cm

height = 5 cm

area:

12 \times 5 = 60 \: cm {}^{2}

3) area of whole polygon

= area of triangle AED + area of rectangle ABCD

= 27 cm² + 60 cm²

= 87 cm²

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Hong compared the player statistics from his teams tennis season. He determined that being taller implies that a player has fast
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<h3>How to interpret the player statistics?</h3>

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Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2)    (1)Q(x2,y2)    (1)

We have R

so i hope thiz helprs you

3 0
3 years ago
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