Find the product of (−x−3)(2x2+5x+8)

Mathematics

2 answers:

Dmitrij [34]3 years ago

8 0

The product is -5x^2-27x-36

sertanlavr [38]3 years ago

7 0

-5x-^27x-36

^=2
Hope this helps

You might be interested in

A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the populat

djverab [1.8K]

Answer:

The function f(x) = 9,000(0.95)^x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
The range values, in the context of the situation, are limited to whole number

Step-by-step explanation:

The "growth" rate is -5%, so the growth factor, the base in the exponential equation, is 1.00-5% =0.95.

Using x=2, we find the population in 2 years is expected to be about ...

f(2) = 9000·0.95^2 ≈ 8123 . . . . about 8120

Using x=4, we find the population in 4 years is expected to be about ...

f(4) = 9000·0.95^4 ≈ 7331 . . . . about 7330

Since population is whole numbers of bees, the range of the function is limited to whole numbers.

The domain of the function is numbers of years. Years can be divided into fractions as small as you want, so the domain is not limited to whole numbers.

The choices listed above are applicable to the situation described.

7 0

3 years ago

How to evaluate the limit

anzhelika [568]

$\displaystyle\lim_{x\to2}\frac{x^2-x+6}{x+2}$

Both the numerator and denominator are continuous at $x=2$ , which means the quotient rule for limits applies:

$\dfrac{\displaystyle\lim_{x\to2}(x^2-x+6)}{\displaystyle\lim_{x\to2}(x+2)}=\dfrac{2^2-2+6}{2+2}=\dfrac84=2$

Perhaps you meant to write that $x\to-2$ instead? In that case, you would have

$\displaystyle\lim_{x\to-2}\frac{x^2-x+6}{x+2}=\lim_{x\to-2}\frac{(x+2)(x-3)}{x+2}=\lim_{x\to-2}(x-3)=-2-3=-5$