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2 years ago

Determine the common factor and HCF for each of the following terms.

Mathematics

1 answer:

Tamiku [17]2 years ago

8 0

Answer:

Step-by-step explanation:

1) 8y = 2 * 2 * 2 * y

12y = 2 * 2 * 3 * y

Common factors = 2 , 2 , y

HCF = 2*2y = 4y.

2) 2 b = 2 *b

3b = 3 * b

Common factor = b

HCF = b

3) 3w = 3 *w

5w² = 5 * w * w

Common factor = w

HCF = w

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Help please! I will mark Brainiest!!

aleksklad [387]

Answer:

It is equal to each other

Step-by-step explanation:

$\sqrt{\frac{1}{x^2}} = \frac{1}{x}\\\sqrt[3]{\frac{1}{x^3}} = \frac{1}{x}$

6 0

2 years ago

An ancient Sicilian legend says that the barber in a remote town who can be reached only by traveling a dangerous mountain road

faust18 [17]

Answer:

No there cannot be.

Step-by-step explanation:

In explaining this question, I would like us to take into account who the barber is,

" the barber is the one who shaves all those, and those only, who do not shave themselves".

This barber cannot be in existence because who would shave him? If he should shave himself then there is a violation of the rule which says he shaves only those who do not shave themselves. If he shaves himself then he ceases to be a barber. And if he does not shave himself then he happens to be under those who must be shaved by the barber, because of what the rule says. But then he is the barber.

This lead us to a contradiction.

Neither is possible so there is no such barber.

4 0

3 years ago

Two brothers, Gethin and David, share a sum of money in the ratio 2:7.

Vitek1552 [10]

12£ and 42£

Step-by-step explanation:

gethin gets 2/9

David gets 7/9

total money is equal to 54

Gethin gets 54x 2/9=12

David gets 54x7/9=42

4 0

3 years ago

Ashley mixes two types of soft drinks with different types of concentration: one soft drink has 20% sugar and the other drink ha

ICE Princess25 [194]

Answer:

Sugar concentration of the mixed soft drink will be 32.5%.

Step-by-step explanation:

Sugar concentration of first drink = 20%

Volume of first soda = 250 ml

Sugar in first soda = 20% of 250 ...... (1)

Sugar concentration of second drink = 45%

Volume of second soda = 250 ml

Sugar in second soda = 45% of 250 ...... (2)

Let $x\%$ be the sugar concentration in resultant mixture.

Volume of mixture = 250 + 250 = 500 ml

Sugar in mixture = $x\%$ of 500 ml ...... (3)

Total sugar concentration (Adding (1) and (2)) and equating it to equation (3):

20% of 250 + 45% of 250 = $x\%$ of 500

$\Rightarrow \dfrac{20}{100} \times 250 + \dfrac{45}{100} \times 250 = \dfrac{x}{100} \times 500\\\Rightarrow 2 \times x = 65\\\Rightarrow x = 32.5\%$

Hence, Sugar concentration of the mixed soft drink will be 32.5%.

8 0

2 years ago

Solve for X: 3-2(x-1)=x-10

lyudmila [28]

$3-2(x-1)=x-10 \\\\ 3-2x+2=x-10 \\\\ -2x+5=x-10 \\\\ -2x-x=-10-5 \\\\ -3x=-15 \\\\ \boxed{x=\frac{-15}{-3}=5}$

6 0

3 years ago

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