Answer:
- 1. C, 2. B, 3. A, 4. C, 5. A, 6. - 7. C, 8. A, 9. (3, 13)
Step-by-step explanation:
<h3>Question 1</h3>
- 4p + 7 = 3 + 4 + 4p
- 4p + 7 = 4p + 7
Both sides are equal, so any value of p makes it right. It means there are infinitely many solutions
<h3>Question 2</h3>
2(3x − 4) = 8 + 2x + 4
Step 2 was wrong, it should be 6x - 8 = 12 + 2x
<h3>Question 3</h3>
- 3/(4z) - 1/(4z) + 3 = 2/(4z) + 5
- 2/(4z) + 3 = 2/(4z) + 5
- 3 = 5
It ends up with false equation, so no solution.
<h3>Question 4</h3>
- 1.6m − 4.8 = −1.6m
- 1.6m + 1.6m = 4.8
- 3.2m = 4.8
- m = 4.8/3.2
- m = 1.5
<h3>Question 5</h3>
Line C: y = x + 14
Line D: y = 3x + 2
- x+ 14 = 3x + 2
- 3x - x = 14 - 2
- 2x = 12
- x = 6
Solution is (6, 20), this is the intersection of lines
<h3>Question 6</h3>
- It should have a graph attached, so ignored
<h3>Question 7</h3>
- b - 2 - 3b = 16 ⇒ -2b = 18 ⇒ b = - 9
Solution is (a, b) = (- 11, - 9)
<h3>Question 8</h3>
Easy method is substitution: w + 2 = 7w - 16
<h3>Question 8</h3>
<u>Easy method is substitution:</u>
- 7x - 8 = 5x - 2
- 7x - 5x = 8 - 2
- 2x = 6
- x = 3
- y = 7*3 - 8 = 21 - 8 = 13
- The point (3, 13) is the solution and it is the intersection of the lines.
Answer:
i think it may be 6
Step-by-step explanationif you add everything together you get 11,10,10,?
so if you do 4+2+6 you get 11.
u did not submit a picture of it
A.) P(t) = P0exp(kt)
P(20/60) = 40 exp(20k/60)
80 = 40 exp(k/3)
exp(k/3) = 80/40 = 2
k/3 = ln(2)
k = 3ln(2)
b.) P(8) = 40(2)^24 = 40(16777216) = 671088640 cells
d.) Rate of change = exp(8k) = exp(8(3ln(2)) = exp(24ln(2)) = exp(16.6355) = 16777216 cells / hour
e.) P(t) = 40(2)^3t; t in hours
1,000,000 = 40(8)^t
25,000 = 8^t
ln(25,000) = t ln(8)
t = ln(25,000)/ln(8) = 4.87 hours
A volume:
V = 3.00 in³
1 in³ = 16.39 cm³
V = 3.00 · 16.39 = 49.17 cm³
0.242 g/cm³ · 49.17 g = 11.899 g² ≈ 11.90 g
Answer: It would weigh 11.90 grams.
