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3 years ago

Solve the inequality 5 - 4x > -x+8

Mathematics

1 answer:

Pavel [41]3 years ago

3 0

Answer:

x<-1

Step-by-step explanation:

5-4x>-x+8

adding 4x to both sides we get

5>3x+8

subtracting eight from both sides we get

-3>3x

dividing by three on both sides we get

-1>x

or x<-1

hope that helps if it does please mark my answer as brainliest.

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elixir [45]

8X + 8 > 7x + 14

subtract 7x and 8 from both sides

x > 6

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3 years ago

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What is the sale price if an item selling for $10 id discounted 20%

lana [24]

Answer:

Step-by-step explanation:

20% of 10 is 2 so 10-2=8

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3 years ago

Which term describes how to determine if a relation given in a table is a function

True [87]

Answer:

A. If none of the output values are repeated, the relation is a function

Step-by-step explanation:

The reason why A is correct stems from the concept of the vertical line test. If each x-value has their own respective output (y-value), then the relation is a function.

Choice B just states that if none of the x-values are repeated. then the relation is a function. This is not correct because it doesnt follow the vertical line test, which analyzes if any y-values are being repeated

Choice C and D doesnt have any correlation with the vertical line test because an x-value doesnt have to equal a y-value to make the relation a function. Vice versa for any y value being equal to any x-value.

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3 years ago

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Firlakuza [10]

918.642 x 1/10 = 91.8642

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3 years ago

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One of the legs of a right triangle measures 9 cm and the other leg measures 11 cm.

ikadub [295]

Answer:

$\boxed {\boxed {\sf 14.2 \ cm}}$

Step-by-step explanation:

Since this is a right triangle, we can use the Pythagorean Theorem to solve for the sides.

$a^2+b^2=c^2$

where a and b are the legs and c is the hypotenuse. In this triangle, we know the legs are 9 centimeters and 11 centimeters, or:

a= 9 cm
b= 11 cm

Substitute these values into the formula.

$(9 \ cm)^{2} +(11 \ cm)^{2} =c^{2}$

Solve the exponents.

(9 cm)²= 9 cm*9 cm=81 cm²

$81 \ cm^{2} +(11 \ cm)^{2} =c^{2}$

(11 cm)²= 11 cm*11 cm= 121 cm²

$81 \ cm^{2} +121 cm^{2} =c^{2}$

Add the values on the left side.

$202 \ cm^{2} =c^{2}$

Since we are solving for c, we must isolate the variable. It is being squared and the inverse of a square is the square root. Take the square root of both sides.

$\sqrt {202 \ cm^{2} }=\sqrt{c^{2} }$