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amm1812
3 years ago
14

A tree that is 10 feet tall casts a shadow that is is 5 feet long. Find the height of a light pole that casts a 9 foot

Mathematics
1 answer:
larisa86 [58]3 years ago
4 0

Answer:

The light pole is 18 feet tall. This is because it casts a shadow that is 9 feet long.

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F - 3/4=5/6. Please answer soon thanks
ad-work [718]
F - 3/4 = 5/6
Add 3/4 to both sides to get
F = 5/6 + 3/4 = 19/12
5 0
3 years ago
For each value of y, determine whether it is a solution to -2y+75-5.<br> Is it a solution?
ser-zykov [4K]

Answer:

• No

• Yes

• Yes

• No

Step-by-step explanation:

To determine if the 4 given values of y are solutions to the inequality, start by solving the inequality. Solving an inequality is just like that of an equation, except that the direction of the sign changes when the inequality is divided by a negative number.

-2y +7≤ -5

Subtract 7 on both sides:

-2y≤ -5 -7

-2y≤ -12

Divide by -2 on both sides:

y≥ 6

This means that the solution can be 6 or greater than 6.

-10 and 3 are smaller than 6 and are not a solutions, while 7 and 6 satisfies the inequality and are therefore solutions.

_______

Alternatively, we can also substitute each value of y into the inequality and check if the value is less than or equal to -5.

Here's an example to check if -10 is a solution.

-2y +7≤ -5

When y= -10,

-2y +7

= -2(-10) +7

= 20 +7

= 27

Since 27 is greater than 5, it is <u>not</u> a solution to the inequality.

3 0
2 years ago
The area of a rectangle is 35 in^2. the length is 7 in. what is the perimeter
Alexus [3.1K]
 The perimeter is 24 inches squared
7 0
3 years ago
Read 2 more answers
What is the solution to -x2 + 5x - 10 = 0?
Korolek [52]

Answer:

No solution

Explanation

−x^2+5x−10=0

Step 1: Use quadratic formula with a=-1, b=5, c=-10.

you plug it in as shown below

and simplify

when you simplify

you get

as shown below

This is no solution....

7 0
3 years ago
find real numbers a, b, and c so that the graph of the function y=ax^2+c contains the points (-1,6), (2,7), and (0,1)
Paraphin [41]
This gives you three simultaneous equations:

6 = a + c
7 = 4a + c
1 = c
 
<u>c = 1
</u>
<u /><u />
If c =1,

6 = a + 1
<u>a = 5
</u>
<u /><u />
This doesn't work in the second equation, so the quadratic that goes through these points is not in the form y = ax^2 + bx + c
Was there supposed to be a b in the equation?




5 0
3 years ago
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