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Nat2105 [25]
2 years ago
15

A 20ft ladder is resting against the side of a house. The base of the ladder is 4ft away from the house. How high above the grou

nd does the ladder touch the house? Round your answer to one decimal place.
Mathematics
1 answer:
goldenfox [79]2 years ago
4 0
19.6.
C^2-A^2=B^2
20^2-4^2=19.595
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Find an equation of the line perpendicular to the graph of 14x-7y=8 that passing through the point at (-2,5).
MAXImum [283]

Answer:

2x + 4y = 16.

Step-by-step explanation:

14x - 7y = 8

Convert to slope-intercept form:

-7y = -14x + 8

y = 2x - 8/7

The slope is 2 so the line perpendicular to it has a slope of -1/2, so we have:

y = 1/2x + c

This line passes through the point (-2, 5) so:

5 = -1/2* (-2) + c

5 = 1 + c

c = 5 - 1 = 4

So our equation is y = -1/2x + 4.

Convert to standard from

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3 years ago
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and you rationalize denominator by multiplying numerator and denominatr by \sqrt{3} so that gives--

\frac{\sqrt{x}}{\sqrt{3}} \cdot \frac{\sqrt{3}}{\sqrt{3}} = \frac{\sqrt{3x}}{3}

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Answer:

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Step-by-step explanation:

Formula: πr^{2}

Plug in data:

9cm is diameter and a radius is half a diameter so the radius is 4.5cm.

π x 4.5^2 = 63.59cm^2

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Step-by-step explanation:

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