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loris [4]
3 years ago
10

PLEASE ANSWER!!

Mathematics
1 answer:
s344n2d4d5 [400]3 years ago
7 0
D
{x}^{2}  + 2xy \\  { ( - 3)}^{2}  + 2( - 3)(5) \\ 9 + 2( - 15) \\ 9 + ( - 30) \\  - 21
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The diameter and height of this cylinder are equal to the side length ,S, of the crude in which the cylinder is inscribed.What e
yulyashka [42]

Answer:

c

Step-by-step explanation:

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3 0
2 years ago
Some researchers have conjectured that stem-pitting disease in peach-tree seedlings might be controlled with weed and soil treat
stiks02 [169]

Answer:

Part A

b. 14.6 ± 7.38

Part B

b. 3.43

Part C

a. P-value < 0.01

Part D

b. There is sufficient evidence to reject the null hypothesis

Step-by-step explanation:

Part A

The given data are;

The number of seedlings in the field = 20

The number of seedlings selected to receive herbicide A = 10

The number of seedlings selected to receive herbicide B = 10

The height in centimeters of seedlings treated with Herbicide A, \overline x _1 = 94.5 cm

The standard deviation, s₁ = 10 cm

The height in centimeters of seedlings treated with Herbicide B, \overline x _2 = 109.1 cm

The standard deviation, s₂ = 9 cm

The 90% confidence interval for μ₂ - μ₁, is given as follows;

\left (\bar{x}_{2}- \bar{x}_{1}  \right )\pm t_{\alpha /2}\sqrt{\dfrac{s_{1}^{2}}{n_{1}}+\dfrac{s_{2}^{2}}{n_{2}}}

The critical-t at 95% and n₁ + n₂ - 2 degrees of freedom is given as follows;

The degrees of freedom, df = n₁ + n₂ - 2 = 10 + 10 - 2 = 18

α = 100% - 90% = 10%

∴ For two tailed test, we have, α/2 = 10%/2 = 5% = 0.05

t_{(0.025, \, 18)} = 1.734

C.I. = \left (109.1- 94.5 \right )\pm 1.734 \times \sqrt{\dfrac{10^{2}}{10}+\dfrac{9^{2}}{10}}

C.I. ≈ 14.6 ± 7.37714603353

The 90% C.I. ≈ 14.6 ± 7.38

b. 14.6 ± 7.38

Part B

With the hypotheses are given as follows;

H₀; μ₂ - μ₁ = 0

Hₐ; μ₂ - μ₁ ≠ 0

The two sample t-statistic is given as follows;

t=\dfrac{(\bar{x}_{2}-\bar{x}_{1})}{\sqrt{\dfrac{s_{1}^{2} }{n_{1}}+\dfrac{s _{2}^{2}}{n_{2}}}}

t-statistic=\dfrac{(109.1-94.5)}{\sqrt{\dfrac{10^{2} }{10}+\dfrac{9^{2}}{10}}} \approx 3.43173361147

The two sample t-statistic ≈ 3.43

b. 3.43

Part C

From the t-table, the p-value, we have, the p-value < 0.01

a. P-value < 0.01

Part D

Given that a significance level of 0.05 level is used and the p-value of 0.01 is less than the significance level, there is enough statistical evidence to reject the null hypothesis

b. There is sufficient evidence to reject the null hypothesis.

4 0
3 years ago
Jay is hanging 160 feet of Christmas garland on the three sides (two on the width and one on the length) of fencing that enclose
Setler [38]

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Given,

The measurement of the Christmas garland = 160 feet

The width of the fencing = w

The length of the fencing, l = 4w - 8

We have to find the length and width of the fencing.

Here,

Perimeter can be taken as 160. Because garland will cover the entire fencing.

Perimeter = 2(l + w)

160 = 2(4w - 8 + w)

160 = 2(5w - 8)

160/2 = 5w - 8

80 + 8 = 5w

88/5 = w

width = 17.6 feet

Now,

l = 4w - 8

l = 4 × 17.6 - 8

l = 70.4 - 8

length = 62.4 feet

That is,

The length of the fencing is 62.4 feet.

The width of the fencing is 17.6 feet.

Learn more about perimeter here:

brainly.com/question/13023749

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Which table represents a function??
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How many combinations of a president, vice-president, secretary, and treasurer can be chosen from a group of 12 students?
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