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Elena L [17]
2 years ago
6

you need to divide up some candies for your children.There are 28 candies.each child gets 1/4 of the candies.how many does each

child get?
Mathematics
1 answer:
Lubov Fominskaja [6]2 years ago
8 0

Answer:

7 each

Step-by-step explanation:

28÷4=7

1/4 of 28=7

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dusya [7]
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4 0
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What is the simplified form of 3/135
PtichkaEL [24]
The answer is 1/45. Hope that helps
3 0
3 years ago
Read 2 more answers
StartLayout enlarged left-brace 1st row 4 x minus 5 y = 5 2nd row negative 0.08 x + 0.10 y = 0.10 EndLayout
FinnZ [79.3K]

Answer:

x = 1.25

y = 0

Step-by-step explanation:

Given

4x - 5y = 5

0.08x + 0.10y = 0.10

Required

Determine the solution

Make x the subject of formula in: 4x - 5y = 5

4x  = 5 + 5y

Divide both sides by 4

\frac{4x}{4}  = \frac{5 + 5y}{4}

x = \frac{5 + 5y}{4}

Substitute x = \frac{5 + 5y}{4} in 0.08x + 0.10y = 0.10

0.08(\frac{5 + 5y}{4}) + 0.10y = 0.10

Solve the fraction

0.02(5 + 5y) + 0.10y = 0.10

Open the bracket

0.1 + 0.1y + 0.10y = 0.10

0.1 + 0.2y = 0.10

Subtract 0.1 from both sides

0.1-0.1 + 0.2y = 0.10 - 0.1

0.2y = 0

Divide both sides by 0.2

y =0

Substitute 0 for y in x = \frac{5 + 5y}{4}

x = \frac{5 + 5*0}{4}

x = \frac{5 + 0}{4}

x = \frac{5 }{4}

x = 1.25

5 0
3 years ago
-3(n+5)=12 what is n
olya-2409 [2.1K]
Divide off -3 from both sides, that leave you with:
n + 5 = -4
Subtract the 5 to the other side
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4 0
3 years ago
How to do both 14) and 16) b/c I have no idea. It is solving rational equations.
Vinvika [58]
Just like at any other time, to add/subtract fractions you need a common denominator.

14)

1/(x^2+2x)+(x-1)/x=1  so we need a common denominator of x(x^2+2x)

[1(x)]/(x(x^2+2x))+[(x-1)(x^2+2x)]/(x(x^2+2x))=[1(x(x^2+2x))]/(x(x^2+2x))

now if you multiply both sides of the equation by x(x^2+2x) you are left with:

x+(x-1)(x^2+2x)=x(x^2+2x)

x+x^3+2x^2-x^2-2x=x^3+2x^2

x^3+x^2-x=x^3-2x^2

x^2-x=-2x^2

3x^2-x=0

x(3x-1)=0, x=0 is an extraneous solution as division by zero is undefined. So the only real solution is:

x=1/3

...

16)

(r+5)/(r^2-2r)-1=1/(r^2-2r)  the common denominator we need r^2-2r so

[r+5-1(r^2-2r)]/(r^2-2r)=1/(r^2-2r), multiplying both sides by r^2-2r yields:

r+5-r^2+2r=1

-r^2+3r+5=1

-r^2+3r+4=0

r^2-3r-4=0

(r-4)(r+1)=0, r^2-2r cannot equal zero, r(r-2)=0, r cannot equal 0 or 2...

r=-1 or 4
8 0
3 years ago
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