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Andreas93 [3]
3 years ago
8

Describe a transformation that would make quadrilateral ABCD into a square

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

ok, relax and listen I’ve got this ok?

Step-by-step explanation:

You just move it up 4 squares to (2, 9), (10,9)

see?you got this I believe in you!!!

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alexdok [17]

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Step-by-step explanation:

1

3 0
4 years ago
Subtract 3/8 from -1/4​
SOVA2 [1]

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6 0
3 years ago
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Katarina [22]

Answer:

Tommy had 56 cents in start and Loren had 7 cents in start.

Step-by-step explanation:

Let,

x be the money Tommy have.

y be the money Loren have.

According to given statement;

Tommy had 8 times more money than Loren.

x = 8y     Eqn 1

Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore

x-14=y+35    Eqn 2

Putting x=8y in Eqn 2

8y-14=y+35\\8y-y=35+14\\7y=49

Dividing both sides by 7

\frac{7y}{7}=\frac{49}{7}\\y=7

Putting y=7 in Eqn 1

x=8(7)\\x=56

Hence,

Tommy had 56 cents in start and Loren had 7 cents in start.

6 0
3 years ago
Help please?
Alla [95]
\bf \begin{array}{clclll}
3^{1001}&\qquad &4^{1002}\\
\uparrow &&\uparrow \\
a&&b
\end{array}\\\\
-----------------------------\\\\
(a+b)^2-(a-b)^2\implies (a^2+2ab+b^2)-(a^2-2ab+b^2)
\\\\\\
a^2+2ab+b^2-a^2+2ab-b^2\implies 2ab+2ab\implies 4ab
\\\\\\
now\qquad 4(3^{1001})(4^{1002})=k12^{1001}\qquad 
\begin{cases}
12^{1001}\\
(4\cdot 3)^{1001}\\
4^{1001}\cdot 3^{1001}
\end{cases}

\bf \\\\\\
4(3^{1001})(4^{1002})=k(4^{1001}\cdot 3^{1001})\implies \cfrac{4(3^{1001})(4^{1002})}{4^{1001}\cdot 3^{1001}}=k
\\\\\\
4\cdot \cfrac{3^{1001}}{3^{1001}}\cdot \cfrac{4^{1002}}{4^{1001}}=k\implies 4\cdot 4^{1002}4^{-1001}=k\impliedby 
\begin{array}{llll}
\textit{same base}\\
\textit{add the}\\
exponents
\end{array}
\\\\\\
4\cdot 4^{1002-1001}=k\implies 4\cdot 4^1=k\implies 16=k
6 0
3 years ago
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