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Andreas93 [3]
3 years ago
8

Describe a transformation that would make quadrilateral ABCD into a square

Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
5 0

Answer:

ok, relax and listen I’ve got this ok?

Step-by-step explanation:

You just move it up 4 squares to (2, 9), (10,9)

see?you got this I believe in you!!!

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Length = 25cm, bredth =60 cm, Volume = 7500cm^3. Find height of a cuboid.
elena-14-01-66 [18.8K]

Answer:

height = 5cm

Step-by-step explanation:

Volume of the cuboid = length x breadth x height

7500 = 25 x 60 x height

height = 7500 / 1500

height = 5

8 0
3 years ago
Read 2 more answers
According to a recent survey, in 2000, 61% of households had one or more pets. Throughout the next decade, this decreased by app
Olin [163]

Answer:

P = 61 - 4x

Step-by-step explanation:

According to a recent survey, in 2000, 61% of households had one or more pets. Throughout the next decade, this decreased by approximately 4% per year.

Therefore, if P represents the percentage of households having pets and x is the number of years after 2000, the expression for P as a function of x will be

P = 61 - 4x (Answer)

5 0
3 years ago
Of those women who are diagnosed to have early-stage breast cancer, one-third eventually die of the disease. Suppose a screening
Finger [1]

Answer:

A) Alternative hypothesis; Ha: p_o > ⅔

B) Null hypothesis;

H0: p_o = ⅔

C) There is sufficient evidence to support the claim that the community screening programme was effective

D) p-value = 0

Its less than the significance value and so we will reject the null hypothesis and conclude that the community screening programme was effective

Step-by-step explanation:

A) We are told that ⅓ of those diagnosed eventually die of the disease. Thus, ⅔ is the fraction that will survive the disease.

Thus, the null hypothesis is;

H0: p_o = ⅔

We are told that a screening programme was started to increase the survival rate. Thus,the alternative hypothesis is;

Ha: p_o > ⅔

B) null hypothesis is;

H0: p_o = ⅔

C) 164 out of the 200 women selected survived the disease.

Thus sample proportion is;

p^ = 164/200

p^ = 0.82

For the z-score value, we will use the formula;

z = (p^ - p_o)/√((p_o(1 - p_o)/n)

Now, p_o = ⅔ = 0.67

Thus;

z = (0.82 - 0.67)/√((0.67(1 - 0.67)/200)

z = 4.51

From online p-value from z-score calculator, we have p-value ≈ 0

This is less than the significant level of 0.05 and therefore we will reject the null hypothesis and conclude that the community screening program was effective.

D) p-value ≈ 0

Reject the null hypothesis

4 0
2 years ago
Simplify(-4.5(-6(5.4
kherson [118]
If this is all multiplication
145.8
8 0
2 years ago
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Grace and Jamal each bought notebooks for school. Grace bought 3 notebooks for $3.90 while Jamal bought 2 notebooks for $2.20. W
ludmilkaskok [199]
3.9/3=$1.30

2.2/2=$1.10

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Hope this help!
7 0
3 years ago
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