Answer:
Tommy had 56 cents in start and Loren had 7 cents in start.
Step-by-step explanation:
Let,
x be the money Tommy have.
y be the money Loren have.
According to given statement;
Tommy had 8 times more money than Loren.
x = 8y Eqn 1
Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore
x-14=y+35 Eqn 2
Putting x=8y in Eqn 2
Dividing both sides by 7
Putting y=7 in Eqn 1
Hence,
Tommy had 56 cents in start and Loren had 7 cents in start.
Answer:
a) P( | X ) = 0.180
b) P(Y | ) = 0.998
Step-by-step explanation:
Let
P(X) - Probability that he acts hungry
P(Y) - Probability that he had ate dinner,
Given,
P(X | Y) = 0.5
P(X | ) = 0.99
P(Y) = 0.9
a.)
P( | X ) =
= = 0.180
⇒P( | X ) = 0.180
b.)
P(Y | ) =
= = 0.998
⇒P(Y | ) = 0.998