Question

HELP ME ASAP PLS

Answer 1

Answer:

Tommy had 56 cents in start and Loren had 7 cents in start.

Step-by-step explanation:

Let,

x be the money Tommy have.

y be the money Loren have.

According to given statement;

Tommy had 8 times more money than Loren.

x = 8y     Eqn 1

Parents gave 35 cents to Loren and Tommy spent 14 cents, therefore

x-14=y+35    Eqn 2

Putting x=8y in Eqn 2

$8y-14=y+35\\8y-y=35+14\\7y=49$

Dividing both sides by 7

$\frac{7y}{7}=\frac{49}{7}\\y=7$

Putting y=7 in Eqn 1

$x=8(7)\\x=56$

Hence,

Tommy had 56 cents in start and Loren had 7 cents in start.