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Len [333]
3 years ago
8

Can someone give the answer to H

Mathematics
2 answers:
Tanya [424]3 years ago
6 0
Does it say anything abt H
White raven [17]3 years ago
6 0
It would be 102,because in the left column the hours are increasing by 3,then 12 times 8.50 equals 102,this should be right let me know if I’m wrong
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Identify the perimeter show work
Helen [10]

Answer:

60

Step-by-step explanation:

The perimeter is the measurement around an object.

So first you multiply the 20 and the 10 by 2.

20 * 2 = 40

10 * 2 = 20

Then, add then up!

40 + 20 = 60

8 0
3 years ago
Read 2 more answers
17.253 to the nearest tenth
Vlad1618 [11]

Answer:

17.3

Step-by-step explanation:

tens  ones. tenths hundredths thousandths

1        7       .   2          5                    3

We are rounding to the nearest tenth

We are rounding the 2 so we look at the 5.  If it is 5 or above we round up.

Since it is, we will round the 2 to a 3

17.3

7 0
3 years ago
Read 2 more answers
Find area of a parallelogram with a height of 8 inches and a base of 14 inches
12345 [234]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{112 \:  {inches} \: ^{2} }}}}}

Step-by-step explanation:

Given,

Height of a parallelogram ( h ) = 8 inches

Base of a parallelogram ( b ) = 14 inches

Area of a parallelogram ( A ) = ?

<u>Finding </u><u>the</u><u> </u><u>area</u><u> </u><u>of</u><u> </u><u>a</u><u> </u><u>parallelogram</u>

<u>\boxed{ \sf{area \: of \: parallelogram \:  =  \: base \:  \times  \: height}}</u>

⇒<u>\sf{area \: of \: parallelogram \:  =  \: 14  \: \times 8}</u>

⇒<u>\sf{area \: of \: parallelogram = 112 \:  {inches}^{2} }</u>

Hope I helped!

Best regards! :D

4 0
3 years ago
What is the circumference of a circle with a 12cm diameter?
pochemuha

Answer:

37.7cm

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
A box is to be constructed from a sheet of cardboard that is 10 cm by 60 cm by cutting out squares of length x by x from each co
Stells [14]

Volume of a rectangular box = length x width x height<span>

From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>

<span>
where x is the height of the box or the side of the equal squares from each corner and turning up the sides

V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x

To maximize the volume, we differentiate the expression of the volume and equate it to zero.

V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>

<span>x^2 - 50/3x + 50 = 0

Solving for x,
x1 = 12.74 ;      Volume = -315.56  (cannot be negative)
x2 = 3.92 ;      Volume = 1056.31

So, the answer would be that the maximum volume would be 1056.31 cm^3.
</span><span>
</span>
6 0
3 years ago
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