If a,b,c are the 3 positive integers
1/a +1/b +1/c > 6/abc
(bc+ac+ab)/abc >6/abc so
(bc+ac+ab)>6
The lowest positive integers that are different are 1,2,3 so the lowest value that (bc+ac+ab) could have is 1•2+2•3+1•3=2+6+3= 11 therefore
1/a +1/b +1/c > 6/abc is true
Answer:
The surface area of ball is 400π sq.cm
Answer:
we need the actual problem
Step-by-step explanation:
please post a photo or just type out the question
Answer:
6/16n is your answer I think
Answer:
D: 6 5/6
Step-by-step explanation:
Solve for a:
a + 7/6 = 8
Put each term in a + 7/6 over the common denominator 6: a + 7/6 = (6 a)/6 + 7/6:
(6 a)/6 + 7/6 = 8
(6 a)/6 + 7/6 = (6 a + 7)/6:
(6 a + 7)/6 = 8
Multiply both sides of (6 a + 7)/6 = 8 by 6:
(6 (6 a + 7))/6 = 6×8
(6 (6 a + 7))/6 = 6/6×(6 a + 7) = 6 a + 7:
6 a + 7 = 6×8
6×8 = 48:
6 a + 7 = 48
Subtract 7 from both sides:
6 a + (7 - 7) = 48 - 7
7 - 7 = 0:
6 a = 48 - 7
48 - 7 = 41:
6 a = 41
Divide both sides of 6 a = 41 by 6:
(6 a)/6 = 41/6
6/6 = 1:
Answer: a = 41/6 or a= 6 5/6
