All categories

3 years ago

Can you help please asap

Mathematics

2 answers:

natita [175]3 years ago

6 0

Answer:

23.5

Step-by-step explanation:

First the shaded area is 28 but there is a triangle so we have to solve the area of the triangle. (formula for triangle: B x H x 1/2) 3 times 3=9 divided by 2=4.5

28-4.5=23.5

Alchen [17]3 years ago

6 0

Multiply the area for the final answer

You might be interested in

A circle has a central angle measuring 7pi/6 radians that intersects an arc of length 18 cm. What is the length of the radius of

pochemuha

Α * R = L where L is the length of the arc of the circle, R is the radius of the circle, and α is the central angle measured in radians, so:

$\cfrac{7 \pi }{6}* R =18 \\ \\ 7*3.14* R=18*6 \\ \\ 21.98 R=108 \\ \\ R=108/21.98 \approx4.9 \ \text{cm}$

7 0

3 years ago

Read 2 more answers

64978256+8734965+709685+1 Who ever answers correctly first gets Brainliest!!!!

anyanavicka [17]

Answer:

64978256+8734965+709685+1 = 74,422,907

5 0

3 years ago

I can't figure out how to do (i + j) x (i x j)for vector calc

Vinil7 [7]

In three dimensions, the cross product of two vectors is defined as shown below

$\begin{gathered} \vec{A}=a_1\hat{i}+a_2\hat{j}+a_3\hat{k} \\ \vec{B}=b_1\hat{i}+b_2\hat{j}+b_3\hat{k} \\ \Rightarrow\vec{A}\times\vec{B}=\det (\begin{bmatrix}{\hat{i}} & {\hat{j}} & {\hat{k}} \\ {a_1} & {a_2} & {a_3} \\ {b_1} & {b_2} & {b_3}\end{bmatrix}) \end{gathered}$

Then, solving the determinant

$\Rightarrow\vec{A}\times\vec{B}=(a_2b_3-b_2a_3)\hat{i}+(b_1a_3+a_1b_3)\hat{j}+(a_1b_2-b_1a_2)\hat{k}$

In our case,

$\begin{gathered} (\hat{i}+\hat{j})=1\hat{i}+1\hat{j}+0\hat{k} \\ \text{and} \\ (\hat{i}\times\hat{j})=(1,0,0)\times(0,1,0)=(0)\hat{i}+(0)\hat{j}+(1-0)\hat{k}=\hat{k} \\ \Rightarrow(\hat{i}\times\hat{j})=\hat{k} \end{gathered}$

Where we used the formula for AxB to calculate ixj.

Finally,

$\begin{gathered} (\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=(1,1,0)\times(0,0,1) \\ =(1\cdot1-0\cdot0)\hat{i}+(0\cdot0-1\cdot1)\hat{j}+(1\cdot0-0\cdot1)\hat{k} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=1\hat{i}-1\hat{j} \\ \Rightarrow(\hat{i}+\hat{j})\times(\hat{i}\times\hat{j})=\hat{i}-\hat{j} \end{gathered}$

Thus, (i+j)x(ixj)=i-j

8 0

1 year ago

A baby is born having a mass of 3,000 grams and gains 200 grams in the following week. How much does the baby weigh one week aft

nignag [31]

Answer:

7 pounds 0.8767 ounces

8 0

4 years ago

Read 2 more answers

(04.02 MC) Solve the system of equations. 5x + y = 9 3x + 2y = 4

goblinko [34]

Answer:

(2,-1)

Step-by-step explanation:

Multiply first equation by 2:

10x + 2y = 18

Subtract the second equation from this so that the 2y terms cancel:

10x - 3x = 18 - 4

7x = 14

x = 2

Plug into first equation to find y:

5(2) + y = 9

10 + y = 9

y = -1

The answer is (2,-1)

7 0

4 years ago

Read 2 more answers

Can you help please asap​

Can you help please asap