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Arturiano [62]
3 years ago
12

Element X is a radioactive isotope such that every 90 years, its mass decreases by half. Given that the initial mass of a sample

of Element X is 30 grams, how much of the element would remain after 12 years, to the nearest whole number?
Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

approximately 27 grams

Work Shown:

Half life formula

y = A*(0.5)^(x/H)

where,

A = starting amount = 30 grams

H = half life period = 90 years

x = number of years that pass by = 12

y = amount left over after x years

Let's plug the values for x, A and H into the formula to find y

y = A*(0.5)^(x/H)

y = 30*(0.5)^(12/90)

y = 27.3516746567466

y = 27 .... rounding to the nearest whole number

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Determine how long it will take an object to rotate through 6.9 revolutions at an angular velocity of 3.1 radians per second. Us
gregori [183]

Answer: 13 . 99 seconds

Step-by-step explanation:

The formula to find how long it will take an object to rotate through 6.9 revolutions at an angular velocity is given as :

t = 2π x number of revolutions / angular velocity

Therefore :

t = 2π x 6.9 / 3.1

t = 2 x 3.142 x 6.9 / 3.1

t = 43.3596/3.1

t = 13. 98696774194

to the nearest tenth

t = 13. 99s

7 0
3 years ago
Can anyone help me solve these linear systems using substitution?
Andre45 [30]

Answer:

1. (2,2)

2. (-20, -1)

3. (4,3)

Step-by-step explanation:

See attached images

4 0
2 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.
Katena32 [7]

Answer:

(a)

5^{-3}=\frac{1}{125}

(b)

-5^{-3}=-\frac{1}{125}

(c)

(-5^{-3})^{-1}=-125

(d)

(-5^{-3})^{0}=1

Step-by-step explanation:

(a)

5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

5^{-3}=\frac{1}{5^3}

5^{-3}=\frac{1}{5\times 5\times 5}

5^{-3}=\frac{1}{125}........Answer

(b)

-5^{-3}

we can use property of exponent

a^{-n}=\frac{1}{a^n}

we get

-5^{-3}=-\frac{1}{5^3}

-5^{-3}=-\frac{1}{5\times 5\times 5}

-5^{-3}=-\frac{1}{125}........Answer

(c)

(-5^{-3})^{-1}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{-1}=(-5)^{-3\times -1}

(-5^{-3})^{-1}=(-5)^3

(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)

(-5^{-3})^{-1}=-125........Answer

(d)

(-5^{-3})^{0}

we can use property of exponent

(a^{n})^m=a^{m\times n}

we get

(-5^{-3})^{0}=(-5)^{-3\times 0}

(-5^{-3})^{-1}=(-5)^0

we can use property

a^0=1

(-5^{-3})^{0}=1........Answer

4 0
3 years ago
HELP WILL GIVE BRAINLIEST FOR ANSWER QUICKLY PLEASE HELP
Helen [10]

Answer:

We have sinθ = 12/13

The  method here is to figure out the value of θ

Using a calculator sin^(-1)(12/13) =67.38°

67.38° is in quadrant 1  so we must substract 67.38° from 180° wich is π

  • 180-67.38= 112.61° ⇒ θ= 112.61°

Now time to calculate cos2θ and cosθ using a calculator

  • cosθ = -5/13
  • cos2θ =  -0.7

The values we got make sense since θ is in quadrant 2 and 2θ in quadrant 3

5 0
3 years ago
bill number is a multilply of 3. rachel number is more than bills number . Geroge number is exactly two times as rachel number.
astra-53 [7]

Answer:

bill is 6 george is 36 and mia is 12

Step-by-step explanation:

6 times 6 is 36 and 1/3 of that is 12. hope I did that right.

8 0
3 years ago
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