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Arturiano [62]
3 years ago
12

Element X is a radioactive isotope such that every 90 years, its mass decreases by half. Given that the initial mass of a sample

of Element X is 30 grams, how much of the element would remain after 12 years, to the nearest whole number?
Mathematics
1 answer:
steposvetlana [31]3 years ago
4 0

Answer:

approximately 27 grams

Work Shown:

Half life formula

y = A*(0.5)^(x/H)

where,

A = starting amount = 30 grams

H = half life period = 90 years

x = number of years that pass by = 12

y = amount left over after x years

Let's plug the values for x, A and H into the formula to find y

y = A*(0.5)^(x/H)

y = 30*(0.5)^(12/90)

y = 27.3516746567466

y = 27 .... rounding to the nearest whole number

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Step-by-step explanation:

You can do long division, which is very very hard to show with typing on a keyboard. You essentially want to divide the leading coefficient for each term. Ill try my best to explain it.

Do \frac{2x^3}{x}=2x^2. Write 2x^2 down. Now multiply (x - 3) by it. Then subtract it from the trinomial.

2x^2*(x-3)=2x^3 -6x^2\\(2x^3 -3x^2-11x+6)-(2x^3-6x^2) = 3x^2-11x+6

Now do \frac{3x^2}{x} =3x. Write that down next to your 2x^2. Multiply 3x by (x - 3) to get:

3x(x-3)=3x^2-9x\\(3x^2-11x+6)-(3x^2-9x)=-2x+6

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Multiply -2 by (x - 3) to get:

-2(x-3)=-2x+6\\(-2x+6)-(-2x+6)=0

Our remainder is 0 so that means (x - 3) goes into that trinomial exactly:

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Answer:

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Step-by-step explanation:

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P = \frac{0.54}{0.88} = 0.6136

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