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Rina8888 [55]
3 years ago
13

Have a great day lads.Don't forget to smile :)

Mathematics
2 answers:
natulia [17]3 years ago
8 0

<u>⊂·       ·⊃</u>

 ║∵ω ∵║

   ≡≡≡≡≡≡≡≡

zysi [14]3 years ago
4 0

Answer:

Aww thank you you too stay safe! :)

Step-by-step explanation:

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How do i find the interval of increase and decrease on a graph? i've tried everything online but nothing pops up
Nataly [62]

The answer is the second option, increase (1,infinity) and decrease (negative infinity,1)

Look at the x axis, not y

4 0
3 years ago
I need help solve this
BARSIC [14]

The set of coordinates in order from top to bottom: (0,3) (1,4) (2,5) (3,6) (4,7)

you get this by adding three to the x value in the ordered pair (x,y)

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5 0
4 years ago
Data collected over time on the utilization of a computer core (as a proportion of the total capacity) were found to possess a r
Marianna [84]

Answer:

The probability that the proportion of the core being used at any particular time will be less than 0.10 is 0.08146

Step-by-step explanation:

\mu =\frac{\alpha }{\alpha +\beta  } = \frac{1}{1 + \frac{\beta}{\alpha} } 1/3   0.33  = 33.33 %

       The Probability of that the proportion of the core being used at any particular time will be less than 0.10 is given by  

PDF = \frac{x^{\alpha -1} (1-x)^{\beta -1} }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du }

where x = 0.1

α = 2 and β = 4

PDF = \frac{0.0729 }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du } = 1.458  

CDF = \frac{\int\limits^{0.1}_0 {t^{\alpha -1} (1-t)^{\beta -1}} \, du }{\int\limits^1_0 {u^{\alpha -1} (1-u)^{\beta -1}} \, du } = 0.08146

The probability that the proportion of the core being used at any particular time will be less than 0.10 = 0.08146.

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4 years ago
Trigonometry please please please please help
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Answer:

104

Step-by-step explanation:

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6 0
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ozzi

<u>drop yall snaps i will add you guys</u>

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