Determina la pendiente de la recta tangente a la curva de la función g(x)=−x−1−−−−−√3 en el punto (1,0).

Mr. calloway is an algebra teacher. every class period he draws a piece of paper out of a hat without looking to determine the n

Eddi Din [679]

The probability of drawing a purple piece during the first class is 7/25 because 7 pieces of paper are purple out of a total of 25 pieces of paper

Since all pieces of paper are returned, the probability of drawing a blue piece during the second class is 2/25 since there are 2 blue pieces out of a total of 25 pieces of paper

The wording is meant to trick you here. If the purple paper from the morning was not replaced before drawing the probability of drawing a blue piece in the second class would increase.

Always remember to reduce fractions where you can

7 0

3 years ago

A tangent to the curve y=6x-x² cuts the x axis at point P. Find the coordinates of P. Help me calc the coordinates please

Ilya [14]

We know that the line is tangent at the point (2,8)

The derivative of the function at x=2 is

$f'(x) = 6-2x \implies f'(2) = 6-4=2$

So, the tangent line passes through the point (2,8) and has slope 2. The equation is

$y-8 = 2(x-2) \iff y = 2x+4$

This line crosses the x axis where y=0:

$0 = 2x+4 \iff 2x = -4 \iff x = -2$

6 0

4 years ago

What is the distance between the y-intercept of the function f (x) = 5(2) and they-intercept of the linear function, g, represen

zlopas [31]

We need to calculate first the function g(x)

First we calculate the slope

$m=\frac{y_2-y_1}{x_2-x_1}=\frac{-5+11}{-6+9}=2$ $g(x)=2(x+9)-11$ $g(x)=2x+7$

the y-intercept of the function g(x) is 7

the y-intercept of the function f(x) is 10

the distance between the y-intercepts of both functions is 3 units

7 0

1 year ago

FREE PTS! Whats your favorite color? Mine is blue skylight

stich3 [128]

Answer:

Mauve Purple and rust Gold

Step-by-step explanation:

1. List ten recommendations for exercise for individuals with the following chronic health conditions:

1. Arthritis

2. Asthma

3. Diabetes

4. Heart Disease Hypertension

5. Osteoporosis

6. Obesity

7. Pregnancy and postpartum( Please use the internet )

6 0

4 years ago

Read 2 more answers

How do you re-write this using only positive exponents? <br><br> 3x^-4/3 (1+2x^5/3)

Kay [80]

$\bf \left.\qquad \qquad \right.\textit{negative exponents}\\\\
a^{-{ n}} \implies \cfrac{1}{a^{ n}}
\qquad \qquad
\cfrac{1}{a^{ n}}\implies a^{-{ n}}
\qquad \qquad 
a^{{{ n}}}\implies \cfrac{1}{a^{-{{ n}}}}
\\\\\\
and\qquad \quad a^{\frac{{ n}}{{ m}}} \implies \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
$

$\bf \cfrac{3x^{-\frac{4}{3}}}{3(1+2x^{\frac{5}{3}})}\implies \cfrac{3}{3}\cdot \cfrac{1}{x^{\frac{4}{3}}}\cdot \cfrac{1}{(1+2x^{\frac{5}{3}})}\implies \cfrac{1}{x^{\frac{4}{3}}(1+2x^{\frac{5}{3}})}$

$\bf \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}}x^{\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^{\frac{5}{3}+\frac{4}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}2x^{\frac{9}{3}}}\implies \cfrac{1}{x^{\frac{4}{3}}+2x^3}
\\\\\\
\cfrac{1}{\sqrt[3]{x^4}+2x^3}\implies \cfrac{1}{x\sqrt[3]{x}+2x^3}\implies \cfrac{1}{x(\sqrt[3]{x}+2x^2)}$

8 0

4 years ago