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Andrej [43]
3 years ago
11

Given that

Mathematics
1 answer:
ra1l [238]3 years ago
3 0

Answer:

-\frac{20}{3}

Step-by-step explanation:

R=9x+8y\\\\4=9x+8(8)\\\\9x+8(8)=4\\\\9x+64=4\\\\9x+64-64=4-64\\\\9x=-60\\\\\frac{9x=-60}{9} \\\\x=-\frac{60}{9}=\boxed{-\frac{20}{3}}

Hope this helps.

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Given that sin theta = 1/4, 0
GaryK [48]
Answer: cos(Θ) = (√15) / 4

Explanation:

The question states:

1) sin(Θ) = 1/4

2) 0 < Θ < π / 2

3) find cos(Θ)

This is how you solve it.

1) Use the fundamental identity (in this part I use α instead of Θ, just for facility of wirting the symbols, but they mean the same for the case).

(cos \alpha )^2 + (sin \alpha )^2 =1

2) From which you can find:

(cos \alpha )^2 = 1 - (sin \alpha )^2

3) Replace sin(α) with 1/4

=> (cos \alpha )^2 = 1 - (1/4)^2 = 1 - 1/16 = 15/16

=> cos \alpha =+/- \sqrt{15/16} = +/- (\sqrt{15} )/4

4) Given that the angle is in the first quadrant, you know that cosine is positive and the final answer is:

cos(Θ) = \sqrt{15} /4.

And that is the answer.
6 0
3 years ago
Same this for me but 6,912 and 288 please help
Svetllana [295]

Answer:

what is the question

Step-by-step explanation:

Questions for answers

4 0
4 years ago
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3 0
3 years ago
Do the rectangular prisms over lap?
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Yes it does







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4 0
3 years ago
Read 2 more answers
How do I solve qudratic equations with factions, like this one:<br> <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B5%7D%7B3%7D%2
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There are several approaches.

(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.

Thus, the quadratic formula would be appropriate here:

         -0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x  = -------------------------------------------------------
                                 2(5/3)
         plus or minus sqrt(100/3)
    = ------------------------------------
                         10/3
            3      10
     = ------* ----------- = sqrt(3)    (answer)
          10     sqrt(3)
8 0
3 years ago
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