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3 years ago

One half times one sixth

Mathematics

2 answers:

Lina20 [59]3 years ago

7 0

The answer is 0.08333333333

crimeas [40]3 years ago

3 0

Answer:

1/12

Step-by-step explanation:

multiple rhe top of the two equations and then multiply the bottom of the two equations

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A bulletin board is 3ft high, it's area is 15 square ft what is the perimeter of the bulletin board

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Write an equation of the line in slope-intercept form

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Joaquin writes the following list of numbers.

swat32

From the given list of numbers, the numbers that are:

rational are 26, -3/2, 0, and 9.

irrational are 5.737737773..., and √45.

Any number that can be written in the form of p/q, where p and q are integers, and q ≠ 0, are called rational numbers.

All terminating and non-terminating recurring decimals are rational numbers.

All the numbers that cannot be represented in the rational form of p/q are irrational numbers.

All non-terminating non-recurring decimals are irrational.

All square roots of imperfect square numbers, that is, surds, are irrational numbers.

In the question, we are asked to classify the given list of numbers into rational and irrational numbers.

5.737737773...: It is an irrational number, since its a non-terminating non-recurring decimal.
26: It is rational as it can be represented in the p/q form (26/1).
√45: It is irrational as it is a square root of an imperfect square number, that is, it is a surd.
-3/2: It is rational as it is in the form p/q.
0: It is rational as it can be represented in the p/q form (0/1).
9: It is rational as it can be represented in the p/q form (9/1).

Thus, from the given list of numbers, the numbers that are:

rational are 26, -3/2, 0, and 9.

irrational are 5.737737773..., and √45.

Learn more about rational and irrational numbers at

brainly.com/question/14994517

#SPJ9

The provided question is incorrect. The correct question is:

Joaquin writes the following list of numbers.

5.737737773..., 26, √45, -3/2, 0, 9.

Which numbers are rational?

Which numbers are irrational?

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1 year ago

The National Cancer Institute estimates that 3.65% of women in their 60s get breast cancer. A mammogram can typically identify c

masha68 [24]

Answer:

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

Step-by-step explanation:

Bayes Theorem:

Two events, A and B.

$P(B|A) = \frac{P(B)*P(A|B)}{P(A)}$

In which P(B|A) is the probability of B happening when A has happened and P(A|B) is the probability of A happening when B has happened.

In this question:

Event A: Positive test.

Event B: Having breast cancer.

3.65% of women in their 60s get breast cancer

This means that $P(B) = 0.0365$

A mammogram can typically identify correctly 85% of cancer cases

This means that $P(A|B) = 0.85$

Probability of a positive test.

85% of 3.65% and 100-95 = 5% of 100-3.65 = 96.35%. So

$P(A) = 0.85*0.0365 + 0.05*0.9635 = 0.0792$

What is the probability that a woman in her 60s who has a positive test actually has breast cancer?

$P(B|A) = \frac{0.0365*0.85}{0.0792} = 0.3917$

39.17% probability that a woman in her 60s who has a positive test actually has breast cancer

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2 years ago