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ale4655 [162]
3 years ago
11

One half times one sixth

Mathematics
2 answers:
Lina20 [59]3 years ago
7 0
The answer is 0.08333333333
crimeas [40]3 years ago
3 0

Answer:

1/12

Step-by-step explanation:

multiple rhe top of the two equations and then multiply the bottom of the two equations

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Questão 02 - Carlos e sua mãe têm juntos atualmente 47 anos. Sabendo que sua mãe ganhou Carlos aos 23 anos, a equação que repres
mariarad [96]

Answer:

x+23 = 47

Step-by-step explanation:

Let age of Carlos is x. It is mentioned that the sum of age of Carlos and his mother is 47 years old. Age of Carlos is 23.

We need to find the equation that represents the sum of Carlos' age with his mother.

x+23 = 47 is the required equation.

Also, we can find the age of Carlos as :

x = 47 - 23

= 24 years

Hence, the correct option is (B).

8 0
2 years ago
Please help due at 10:00!!!!!!!!!
katovenus [111]

Answer:

<em>9 sheep and 5 goats</em>

Step-by-step explanation:

s + g = 14

125s + 75g = 1500

125( 14 - g ) + 75g = 1500

1750 - 125 g + 75g = 1500

50g = 250

g = <em>5 goats</em>

s = <em>9 sheep</em>

6 0
2 years ago
What is the answer to <br> a/-2 = 8
WARRIOR [948]

Answer:

-16

Step-by-step explanation:

a/-2=8

you multiply -2 on both side a/-2(-2)=8(-2)

-2 cancels out one the one side

your final answer is a= -16

3 0
3 years ago
If $10,000 is invested in an account at 4.8% annual simple interest, how long will it take for the account balance
Lesechka [4]
10000+4.8%=10480
10480+4.8%=10983.04
10983.04+4.8%=11510.22592


so 3 years
7 0
3 years ago
Read 2 more answers
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
boyakko [2]
PART A
s = <span>the number of packets of strawberry wafers ;
c = </span><span>the number of packets of chocolate wafers ;
3 </span>× s + 1 × <span>c = 30 ;
s + c = 22 ;

PART B

</span>The method of solving "by substitution"<span> works by solving one of the equations (you choose which one) for one of the variables (you choose which one), and then plugging this back into the other equation, "substituting" for the chosen variable and solving for the other. Then you back-solve for the first variable.
</span>
c = 30 - 3s;
s + ( 30 - 3s ) = 22;
30 - 2s = 22;
30 - 22 = 2s;
8 = 2s;
s = 4 ;
c = 30 - 12 ;
c = 18 ;

4 0
3 years ago
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