Solid liquid and gas
when it changes from a:
solid
to a
liquid: melting, fusion
gas: sublimation
liquid
to a
solid:freezing
gas:vaporization
gas
to a
solid:condensation, deposition
liquid: condensation, liquefacation
Answer:
-1.37 kJ/mol
Explanation:
The expression for the calculation of the enthalpy of dissolution of [tex[NH_4NO_3[/tex] is shown below as:-
Where,
is the enthalpy of dissolution of [tex[NH_4NO_3[/tex]
m is the mass
C is the specific heat capacity
is the temperature change
Thus, given that:-
Mass of ammonium nitrate = 5.60 g
Specific heat = 4.18 J/g°C
So,
Negative sign signifies loss of heat.
Also, 1 J = 0.001 kJ
So,

Also,
Molar mass of [tex[NH_4NO_3[/tex] = 80.043 g/mol
The formula for the calculation of moles is shown below:
Thus,

Thus, 
<span> In order to create a complete full outer shell of electrons.
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Answer:Metals are an excellent conductor of electricity and heat because the atoms in the metals form a matrix through which outer electrons can move freely. Instead of orbiting their respective atoms, they form a sea of electrons that surround the positive nuclei of the interacting metal ions.
Explanation:
This particular law is a gas law, called Charle's Law. The formula is:
V1 V2
---- = ----
T1 T2
So we know our original volume is 4.0L, so we would plug that into our V1. We know T1 is the 30 degrees, since it relates to our original volume. However, we need to convert it to kelvin. We do this simply by adding 273 degrees to the 30 degrees, since 273 is the constant for kelvin.
We do not know our second volume, however we know out T2. It is -8 degrees, and don't forget to convert it to Kelvin.
So, when we plug all of these numbers into the equation, we are left with V2 to find. To do this we cross multiply (V1 x T2) and then divide by T1. That leaves us with the number for V2. Don't forget to round to the least # of sig figs! And you can divide V1 by T1, and then divide V2 by T2, to ensure your answers are the same, since they are directly porportional and need to be equal to each other.
Hope I could help!