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Nata [24]
3 years ago
15

Calculate the percent oxygen in potassium chlorate (KClO3)

Chemistry
2 answers:
andreev551 [17]3 years ago
7 0

Molar Mass of KCLO3

= 39 + 35.5 + 48 g

= 122.5 g .

So , percentage of Potassium ( K )

= 39 / 122.5 * 100 %

= 31.83 %

Now , percentage of Chlorine ( Cl )

= 35.5 / 122.5 * 100 %

= 28.97 %

So, finally, percentage of Oxygen ( O )

= 48 / 122.5 * 100 %

= 39.18 %

Law Incorporation [45]3 years ago
6 0

Answer:

39.18⁒

Explanation:

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7 0
3 years ago
what volume of 1.75 m hcl in liters is needed to react completely (with nothing left over) with 0.750 l of 0.100 m na2co3 ?
Evgesh-ka [11]

The balance chemical equation is :

2HCL + Na2CO3 -----> 2NaCl + H2O + CO2

According to Question,

Given,

Molarity of HCL = 1.75 m

Sodium Carbonate (Na2CO3) = 0.100 m

For finding out the molarity,

c = n solute / Vsolution  => n = c.Vsolution

nCO^2-3 = 0.100 mol L^-1 . 0.750 L = 0.0750 moles of CO^2-3

0.0750 moles of CO^2-3 . 2 moles H3O^+ / 1 mole CO^2-3

= 0.150 moles of  H3O^+

As we have already know the molarity of HCL , we easily calculate what volumes by many moles.

c = nsolute / Vsolution => Vsolution = nsolute / c

VH3O^+ = 0.150 moles / 1.75 mol L^-1 =  0.0857 L

To know more about Molarity here :

brainly.com/question/8732513?referrer=searchResults

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6 0
1 year ago
What method would you use to obtain pure water from a mixture of water and ink
mel-nik [20]

Answer: Distillation

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5 0
4 years ago
Read 2 more answers
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