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Nata [24]
3 years ago
15

Calculate the percent oxygen in potassium chlorate (KClO3)

Chemistry
2 answers:
andreev551 [17]3 years ago
7 0

Molar Mass of KCLO3

= 39 + 35.5 + 48 g

= 122.5 g .

So , percentage of Potassium ( K )

= 39 / 122.5 * 100 %

= 31.83 %

Now , percentage of Chlorine ( Cl )

= 35.5 / 122.5 * 100 %

= 28.97 %

So, finally, percentage of Oxygen ( O )

= 48 / 122.5 * 100 %

= 39.18 %

Law Incorporation [45]3 years ago
6 0

Answer:

39.18⁒

Explanation:

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If a compound with a density of 9.0 g/cm^3 occupies 37.6 in^3, what is its mass in kg?
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How many atoms are found in 4.75 moles of Fe?
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Answer:

The answer to your question is below

Explanation:

a)

Number of atoms = ?

moles of Fe = 4.75

-Use proportions to solve this problem

                            1 mol of Fe --------------------- 6.023 x 10²³ atoms

                          4.75 moles  ---------------------  x

                            x = (4.75 x 6.023 x 10²³) / 1

                            x = 2.86 x 10²⁴ / 1

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b)

Number of moles = ?

moles of 1.058 moles of H₂O

I think this question is incorrect, maybe you wish to know the number of atoms or grams of H₂O.

c)

Number of atoms = ?

moles of Fe = 0.759

                       1 mol of Fe ------------------ 6.023 x 10²³ atoms

                       0.759 moles ---------------  x

                        x = (0.759 x 6.023 x 10²³) / 1

                        x = 4.57 x 10²³ / 1

Number of atoms of Fe = 4.57 x 10²³ atoms

d)

Number of molecules = ?

moles of H₂O = 3.5 moles

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                         3.5 moles       ------------------   x

                          x = (3.5 x 6.023 x 10²³) / 1

                          x = 2.11 x 10²⁴ molecules

Number of molecules = 2.11 x 10²⁴                                                                        

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