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aev [14]
3 years ago
5

Anabolic reactions _______ bonds, whereas catabolic reactions __________ bonds. A. decrease; increase. B. break; make C. weaken;

strengthen D. loosen; tighten. E. make; break
Chemistry
1 answer:
nexus9112 [7]3 years ago
6 0

Answer:

The corrext answer is E. make; break

Explanation:

In living organisms, the metabolism is either anabolic or catabolic where anabolic metabolism is energy consuming and catabolic metabolism is eneegy releasesing. It should however be noted that anabolic reaction builds or biosynthesize new mollecular structures while catabolic reaction breaks down complex structure bonds into simple structures

The braking down of bonds in catabolic reations realeses energy to sustain the anabolic rection process for the formation of new bonds

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13. What is the frequency of a wave that has a wavelength of 2.73 x 10-7m?​
ella [17]

Answer:

f = 1.09 × 10¹⁵ Hz

Explanation:

Given data:

Frequency of wave = ?

Wavelength of wave = 2.73 ×10⁻⁷ m

Solution:

Formula:

Speed of light = frequency × wavelength

speed of light = 3× 10⁸ m/s

by putting values,

3× 10⁸ m/s = f × 2.73 ×10⁻⁷ m

f = 3× 10⁸ m/s  / 2.73 ×10⁻⁷ m

f = 1.09 × 10¹⁵s⁻¹

s⁻¹ = Hz

f = 1.09 × 10¹⁵ Hz

4 0
3 years ago
A sample of oxygen gas has a volume of 45.8 mL when its pressure is 0.492 atm. What
White raven [17]

Answer:

<h2> a. 23.6</h2>

Explanation:

P_1=0.492\:atm\\V_1 = 45.8\:ml\\V_2 = ?\\P_1 = 0.954\:atm\\\\Boyle's Law = P_1V_1 = P_2V_2\\\\Lets \:make\: V \:subject\:of\:the\:formula\\\\\frac{P_1V_1}{P_2} = \frac{P_2V_2}{P_2} \\ \\V_2 =\frac{P_1V_1}{P_2} \\V_2 = \frac{0.492\times45.8}{0.954}\\ \\V_2 = \frac{22.5336}{0.954} \\\\V_2  = 23.620\\\\V_2 = 23.6

4 0
3 years ago
Read 2 more answers
Your science teacher gives you three liquids to pour into a jar. After pouring all of them into the jar, the liquids layer as se
sweet-ann [11.9K]

Answer:

density

Explanation:

6 0
3 years ago
Which of these have the same number of particles as 1 mole of water H2O
Fed [463]

Answer:

It is equal to Avogadro's number (NA), namely 6.022 x1023. If we have one mole of water, then we know that it will have a mass of 2 grams (for 2 moles of H atoms) + 16 grams (for one mole O atom) = 18 grams.

Explanation:

The question is not very much clear.

If you are asking for molecules then 1 mole water= 6.023 * 10^23

If you are asking for atoms then 1 mole water= 6.023 * 10^23 * 3

If you are asking for particles then,

So, in your example you would have one mole of water molecules. If you dissociated those water molecules, than you would end up with 2 moles of hydrogen atoms, and one mole of oxygen atoms.

I hope that was helpful!

H=1 proton,1 electron

O=8 protons,8 neutrons and 8 electrons

total particles in one H2O molecule-28

total no. of particles in 1 mole of water- 6.023 * 10^23 * 28

8 0
3 years ago
18. Focal length is a length which lies between
Jet001 [13]

Answer:

Lens and focal point is the correct answer.

7 0
3 years ago
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