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kramer
3 years ago
10

5x^2+ 15x – 140 = 0 Solve for x

Mathematics
2 answers:
nekit [7.7K]3 years ago
5 0

Answer:

x = 4, -7

Step-by-step explanation:

1) Factor out the common term 5.

5( {x}^{2}  + 3x - 28) = 0

2) Factor x² + 3x - 28.

5(x - 4)(x + 7) = 0

3) Solve for x.

x = 4, -7

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u>,</u><u> </u><u>-7</u><u>.</u>

MrRissso [65]3 years ago
3 0

Answer:

x = 4, -7

Step-by-step explanation:

1. <u>Solve the equation using the quadratic formula</u>

The <u>Quadratic formula</u> provides the solution for Ax^{2} +Bx+C=0

in which A, B, and C are numbers (or coefficients), as follows:

\frac{-b+\sqrt{b^{2}-4ac } }{2a}

2. <u>Determine the quadratic equation’s coefficients A, B, and C</u>

The <u>coefficients</u> of our equation, 5x^{2} +15x-140=0, are:

A = 5

B = 15

C = -140

3. <u>Plug these coefficients into the quadratic formula</u>

<u />\frac{-b+\sqrt{b^{2}-4ac } }{2a}=\frac{-15+\sqrt{15^{2}-4x5x-140 } }{2x5}

Calculate the expression inside the parentheses.

Simplify exponents and square roots.

\frac{-15+\sqrt{15^{2}-4x5x-140 } }{2x5}

\frac{-15+\sqrt{225-4x5x-140 } }{2x5}

Perform any multiplication or division, from left to right.

\frac{-15+\sqrt{225-20x-140 } }{2x5}

\frac{-15+\sqrt{225-2800 } }{2x5}

\frac{-15+\sqrt{3025} }{2x5}

\frac{-15+\sqrt{3025} }{10}

to get the result:

x=\frac{-15+\sqrt{3025} }{10}

4. <u>Simplify square root</u>

Simplify 3025 by finding its prime factors.

                    3025

                   /         \

                 /             \

             5                  605

              /                    \

            /                        \

          5                          "<u>121</u>"

           /                            \

         /                                \

        11                                11

The prime factorization of 3025 is 5² • 11²

Write the prime factors.

\sqrt{3025} = √5 • 5 • 11 • 11

Group the prime factors into pairs and rewrite in exponent form.

√5 • 5 • 11 • 11 = \sqrt{5^{2}x11^{2}  }

Use rule \sqrt{x^{2} } = x to simplify futher.

\sqrt{5^{2}x11^{2}} = 5 • 11

5 • 11 = 55

5. Solve the equation for x

x = \frac{-15+55}{10}

The ± means two answers are possible:

x = 4

or

x = - 7

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Answer:

Experimental probability = 9 / 100

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Step-by-step explanation:

The experimental probability of an event is written as :

P = number of times event occur / total number of trials

Experimental probability is based on the outcome of an experiment that has taken place.

Theoretical probability is based on expected outcome of an event.

P = number of expected or required outcomes / total possible outcomes

Experimental probability of choosing the name Michael is :

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Experimental probability = 9 / 100 = 0.09

Theoretical probability of choosing michael:

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If the number of names in hat was different from 7, then the theoretical probability will change.

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You have 2 job offers with the following options. Option 1: You are paid $30
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Cuanto es la respuesta de -126=14k?
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Answer:

\boxed{ \bold{ \huge{ \boxed{ \text{k =   - 9}}}}}

Step-by-step explanation:

\star{ \text{ - 126 = 14k}}

\text{step \: 1 \: : Intercambia los lados de la ecuación}

\hookrightarrow{ \sf{14k =  - 126}}

\text{step \: 2 : Divide ambos lados por 14}

\hookrightarrow{ \sf{ \frac{14k}{14}  =  \frac{ - 126}{14}}}

\text{step \: 3 \:  : Calcular}

\hookrightarrow{ \sf{k =  - 9}}

\text{el valor de k es  - 9}

------------------------------------------------------------

Translation in English:

Step 1 : Swap the sides of the equation

Step 2 : Divide both sides by 14

Step 3 : Calculate

\sf{Hope \: i \: helped ! }

\sf{Best \: regards !!}

~\sf{TheAnimeGirl}

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As per the question statement, We are given a pair of parallel lines which is cut by a transversal. We are supposed to mark the following angles.

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Here is an attached image of the same with angles marked on it.

Alternate Interior Angles: ∠3 = ∠5 and ∠4=∠6

Alternate Exterior Angles: ∠2=∠8 and ∠1=∠7

Corresponding Angles: ∠1=∠5 , ∠4=∠8 , ∠3=∠7 and ∠2=∠6

Consecutive Interior Angles: ∠4=∠5 and ∠3=∠6

  • Parallel Lines: Parallel lines are those straight lines that are, no matter how far they are extended, always the same distance apart from one another.
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To learn more about Transversal Line click on the link given below:

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