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kramer
3 years ago
10

5x^2+ 15x – 140 = 0 Solve for x

Mathematics
2 answers:
nekit [7.7K]3 years ago
5 0

Answer:

x = 4, -7

Step-by-step explanation:

1) Factor out the common term 5.

5( {x}^{2}  + 3x - 28) = 0

2) Factor x² + 3x - 28.

5(x - 4)(x + 7) = 0

3) Solve for x.

x = 4, -7

<u>Therefor</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>x</u><u> </u><u>=</u><u> </u><u>4</u><u>,</u><u> </u><u>-7</u><u>.</u>

MrRissso [65]3 years ago
3 0

Answer:

x = 4, -7

Step-by-step explanation:

1. <u>Solve the equation using the quadratic formula</u>

The <u>Quadratic formula</u> provides the solution for Ax^{2} +Bx+C=0

in which A, B, and C are numbers (or coefficients), as follows:

\frac{-b+\sqrt{b^{2}-4ac } }{2a}

2. <u>Determine the quadratic equation’s coefficients A, B, and C</u>

The <u>coefficients</u> of our equation, 5x^{2} +15x-140=0, are:

A = 5

B = 15

C = -140

3. <u>Plug these coefficients into the quadratic formula</u>

<u />\frac{-b+\sqrt{b^{2}-4ac } }{2a}=\frac{-15+\sqrt{15^{2}-4x5x-140 } }{2x5}

Calculate the expression inside the parentheses.

Simplify exponents and square roots.

\frac{-15+\sqrt{15^{2}-4x5x-140 } }{2x5}

\frac{-15+\sqrt{225-4x5x-140 } }{2x5}

Perform any multiplication or division, from left to right.

\frac{-15+\sqrt{225-20x-140 } }{2x5}

\frac{-15+\sqrt{225-2800 } }{2x5}

\frac{-15+\sqrt{3025} }{2x5}

\frac{-15+\sqrt{3025} }{10}

to get the result:

x=\frac{-15+\sqrt{3025} }{10}

4. <u>Simplify square root</u>

Simplify 3025 by finding its prime factors.

                    3025

                   /         \

                 /             \

             5                  605

              /                    \

            /                        \

          5                          "<u>121</u>"

           /                            \

         /                                \

        11                                11

The prime factorization of 3025 is 5² • 11²

Write the prime factors.

\sqrt{3025} = √5 • 5 • 11 • 11

Group the prime factors into pairs and rewrite in exponent form.

√5 • 5 • 11 • 11 = \sqrt{5^{2}x11^{2}  }

Use rule \sqrt{x^{2} } = x to simplify futher.

\sqrt{5^{2}x11^{2}} = 5 • 11

5 • 11 = 55

5. Solve the equation for x

x = \frac{-15+55}{10}

The ± means two answers are possible:

x = 4

or

x = - 7

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A theater sells tickets for a concert. Tickets for lower-level seats sell for $55 each, and tickets for upper-level seats sell f
Alex

Answer: Lower level tickets = 85

Upper level tickets = 156

Step-by-step explanation: The first thing we shall do is assign letters to the unknown variables. We'll start by calling the lower level tickets L, and the upper level tickets P.

Next is we use the clues we've been given. Since the theater sold 241 tickets, we can write the expression

L + P = 241 ---------------- (1)

Next thing we're told is that lower level tickets were sold for $55 while upper level tickets were sold for $30. If total ticket sales was $9355, then we can write another expression

55L + 30P = 9355 -------(2)

We now have a pair of simultaneous equations

L + P = 241 ---------------------(1)

55L + 30P = 9355 ---------(2)

From equation (1), we shall make L the subject of the equation

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Collecting like terms we now have

13255 - 9355 = 55P - 30P

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Divide both sides of the equation by 25

156 = P.

This means upper level tickets sold were 156 in number.

Substitute for the value of P in equation (1)

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Subtract 156 from both sides of the equation

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L = 85

Therefore, lower level tickets sold were 85 and

Upper level tickets sold were 156

5 0
4 years ago
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