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trapecia [35]
3 years ago
15

Decide whether the following statement is true or false. If the degree of the numerator of a rational function equals the degree

of the​ denominator, then the rational function has a horizontal asymptote. Choose the correct answer below.
A. The statement is true because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has a horizontal asymptote that is equal to the product of the leading coefficients.

B. The statement is true because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has a horizontal asymptote that is equal to the ratio of the leading coefficients.

C. The statement is false because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has no horizontal or oblique asymptotes.

D. The statement is false because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has an oblique asymptote that is equal to the quotient found using polynomial division.
Mathematics
1 answer:
Alona [7]3 years ago
7 0

B. The statement is true because if the degree of the numerator of a rational function equals the degree of the​ denominator, then the rational function has a horizontal asymptote that is equal to the ratio of the leading coefficients.

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Charlie is standing 45 feet from the base of 100 foot tall tree. What is the angle of elevation from him to the kite stuck on to
galben [10]
Hey. Let me help you on this one.

In order for us to solve this problem easier, let's break it apart. We can also graph the triangle so we get visual of this problem.

I drew a quick graph for you to easier understand this question. As you can see, Charlie is standing below the tree 45 feet from it, and we need to find the unknown angle measure.

Let's form a SOHCAHTOA function which you have probably already learned in your Geometry course.

First of all let's identify our sides. The side opposite of the right triangle is a Hypotenuse, and the side that's 45 feet is adjacent, since it's adjacent to the unknown angle.

We know that we need to use Cos (Cosine) with negative power to it in order to solve this question, since we are looking for the unknown angle measure.

Let's form the function which Cos, Hypotenuse, and Adjacent side.

Cos^{-1} =45/100

Now, let's solve the left part of this function


Cos^{-1} =0.45

Awesome. You will need to use your calculator for this part. Find the value of 0.45 when negative Cosine is used on it.

Cos^{-1} =0.45
63.25631605

Awesome. Let's round this number to the closest tenth

63.3 is the rounded value we have discussed below.

Answer: 63.3 degrees is the unknown measure of the angle

5 0
3 years ago
Please could you find the answers to the questions in the attachment.
Fudgin [204]
(\frac{x1+x2}{2} , \frac{y1+y2}{2})we need 3 equations
1. midpoint equation which is  (\frac{x1+x2}{2} , \frac{y1+y2}{2}) when you have 2 points

2. distance formula which is D= \sqrt{(x2-x1)^{2}+(y2-y1)^{2}}

3. area of trapezoid formula whhic is (b1+b2) times 1/2 times height


so

x is midpoint of B and C
B=11,10
c=19,6
x1=11
y1=10
x2=19
y2=6
midpoint=(\frac{11+19}{2} , \frac{10+6}{2})
midpoint=(\frac{30}{2} , \frac{16}{2})
midpoint= (15,8)

point x=(15,8)



y is midpoint of A and D
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
midpoint=(\frac{5+21}{2} , \frac{8+0}{2})
midpoint=(\frac{26}{2} , \frac{8}{2})
midpoint=(13,4)

Y=(13,4)



legnths of BC and XY
B=(11,10)
C=(19,6)
x1=11
y1=10
x2=19
y2=6
D= \sqrt{(19-11)^{2}+(6-10)^{2}}
D= \sqrt{(8)^{2}+(-4)^{2}}
D= \sqrt{64+16}
D= \sqrt{80}
D= 4 \sqrt{5}
BC=4 \sqrt{5}





X=15,8
Y=(13,4)
x1=15
y1=8
x2=13
y2=4
D= \sqrt{(13-15)^{2}+(4-8)^{2}}
D= \sqrt{(-2)^{2}+(-4)^{2}}
D= \sqrt{4+16}
D= \sqrt{20}
D= 2 \sqrt{5}
XY=2 \sqrt{5}


the thingummy is a trapezoid
we need to find AD and BC and XY
we already know that BC=4 \sqrt{5} and XY=2 \sqrt{5}

AD distance
A=5,8
D=21,0
x1=5
y1=8
x2=21
y2=0
D= \sqrt{(21-5)^{2}+(0-8)^{2}}
D= \sqrt{(16)^{2}+(-8)^{2}}
D= \sqrt{256+64}
D= \sqrt{320}
D= 4 \sqrt{2}
AD=4 \sqrt{2}


so we have
AD=4 \sqrt{2}
BC=4 \sqrt{5} 
XY=2 \sqrt{5}

AD and BC are base1 and base 2
XY=height
so
(b1+b2) times 1/2 times height
(4 \sqrt{2}+4 \sqrt{5}) times 1/2 times 2 \sqrt{5} =
(4 \sqrt{2}+4 \sqrt{5}) times \sqrt{5} [/tex] =
4 \sqrt{10}+4*5=4 \sqrt{10}+20=80 \sqrt{10}=252.982


























X=(15,8)
Y=(13,4)
BC=4 \sqrt{5}
XY=2 \sqrt{5}
Area=80 \sqrt{10} square unit or 252.982 square units







7 0
3 years ago
If this trapezoid is moved through the
jeka94

Answer:

Step-by-step explanation:

A(-6,2) =>A'(-5, -1)

B(-5,4) =>B'( -4,1)

C(-2,4)=> C'(-1,1)

D( 1,2) => D'(2,-1)

we move all these points to (x+1, y-3)

7 0
2 years ago
Solve this problem thanks
vovikov84 [41]

The three missing lengths are the left hypotenuse, x, the middle altitude, y, and the right hypotenuse, z.


9/y = y/16


y^2 = 9 * 16


y^2 = 144


y = 12


9^2 + 12^2 = x^2


x^2 = 225


x = 15


12^2 + 16^2 = z^2


z^2 = 400


z = 20


From left to right, the sides measure 15, 12, and 20 units.

5 0
3 years ago
Read 2 more answers
What is (-i)5?<br> A -1<br> B 1<br> C -I<br> D i
dezoksy [38]

Answer:

-i^5=-i

Step-by-step explanation:

rewrite the equation ;

i^4=1

I^4 *-i = 1*-i=-i

8 0
3 years ago
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