Which equation is graphed?

True or False: The following relation is a function. {(−5,−7),(0,4),(−5,3),(9,4)}

snow_lady [41]

the answer is that it is false

5 0

3 years ago

Please write a equation for this line

Eduardwww [97]

Answer:

y=-x

Step-by-step explanation:

It's going left one by one, meaning the slope is negative and has a slope of -1 or -x.

3 0

3 years ago

The average college lecture hall (auditorium) can seat 60 students with a standard deviation of 21. Assume that a total of 60 le

fiasKO [112]

Answer:

The standard deviation of the sample mean is $\sigma _ {\= x } = 2.711$

Step-by-step explanation:

From the question we are told that

The mean is $\= x = 60$

The standard deviation is $\sigma = 21$

The sample size is $n = 60$

Generally the standard deviation of the sample mean is mathematically represented as

$\sigma _ {\= x } = \frac{\sigma }{\sqrt{n} }$

substituting values

$\sigma _ {\= x } = \frac{ 21 }{\sqrt{60} }$

$\sigma _ {\= x } = 2.711$

4 0

3 years ago

Discuss the continuity of the function on the closed interval.Function Intervalf(x) = 9 − x, x ≤ 09 + 12x, x > 0 [−4, 5]The f

quester [9]

Answer:

It is continuous since $\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$

Step-by-step explanation:

We are given that the function is defined as follows $f(x) = 9-x, x\leq 0$ and $f(x) = 9+12x, x>0$ and we want to check the continuity in the interval [-4,5]. Note that this a piecewise function whose only critical point (that might be a candidate of a discontinuity) x=0 since at this point is where the function "changes" of definition. Note that 9-x and 9+12x are polynomials that are continous over all $\mathbb{R}$ . So F is continous in the intervals [-4,0) and (0,5]. To check if f(x) is continuous at 0, we must check that

$\lim_{x\to 0^{-}} = f(0) = \lim_{x \to 0^{+} f(x)$ (this is the definition of continuity at x=0)

Note that if x=0, then f(x) = 9-x. So, f(0)=9. On the same time, note that

$\lim_{x\to 0^{-}} f(x) = \lim_{x\to 0^{-}} 9-x = 9$ . This result is because the function 9-x is continous at x=0, so the left-hand limit is equal to the value of the function at 0.

Note that when x>0, we have that f(x) = 9+12x. In this case, we have that

$\lim_{x\to 0^{+}} f(x) = \lim_{x\to 0^{+}} 9+12x = 9$ . As before, this result is because the function 9+12x is continous at x=0, so the right-hand limit is equal to the value of the function at 0.