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Molodets [167]
3 years ago
13

Find the total surface area of a cylinder whose diameter is 28 cm and height is 11 cm.

Mathematics
2 answers:
garri49 [273]3 years ago
6 0

Answer:

2199.11 (with pi)

2198 (with 3.14)

Step-by-step explanation:

A=2πrh+2πr²

A=2π(14)(11)+2π(14)²

A=2π(154)+2π(196)

A=2(483.56)+2(615.44)

A=967.12+1230.88

Scorpion4ik [409]3 years ago
4 0
59 cm yun ang sagot sa tanong mo
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Step-by-step explanation:

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$2,000 IN AN ACCOUNT THAT PAID 6.25% SIMPLE INTEREST ANNUALLY
valkas [14]
\bf ~~~~~~ \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$2000\\
r=rate\to 6.25\%\to \frac{6.25}{100}\to &0.0625\\
t=years\to &3
\end{cases}
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8 0
3 years ago
Suppose the sediment density (g/cm) of a randomly selected specimen from a certain region is normally distributed with mean 2.65
Verizon [17]
A) 0.9803; 0.4803
B) 32

We calculate the z-score for this problem by using the formula:

z=\frac{X-\mu}{\frac{\sigma}{\sqrt{n}}}

Using our formula, we have:

z=\frac{3.00-2.65}{\frac{0.85}{\sqrt{25}}}=2.06

Using a z-table (http://www.z-table.com) we see that the area to the left of, less than, this score is 0.9803.

To find the probability it is between the mean and this, we subtract the probability associated with the mean (0.5) from this:
0.9803 - 0.5 = 0.4803.

To find B, we first find the z-score for this.  Using a z-table (http://www.z-table.com) we see that the closest z-score would be 2.33.  We then set up our equation as

2.33=\frac{3.00-2.65}{\frac{0.85}{\sqrt{n}}}=\frac{0.35}{\frac{0.85}{\sqrt{n}}}
\\
\\2.33=0.35\div \frac{0.85}{\sqrt{n}}=0.35\times \frac{\sqrt{n}}{0.85}

Multiplying both sides by 0.85 we have
2.33(0.85) = 0.35√n
1.9805 = 0.35√n

Divide both sides by 0.35:
1.9805/0.35 = √n

Square both sides:
(1.9805/0.35)² = n
32 ≈ n
8 0
3 years ago
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