Answer:
(x, y) = (2, 5)
Step-by-step explanation:
I find it easier to solve equations like this by solving for x' = 1/x and y' = 1/y. The equations then become ...
3x' -y' = 13/10
x' +2y' = 9/10
Adding twice the first equation to the second, we get ...
2(3x' -y') +(x' +2y') = 2(13/10) +(9/10)
7x' = 35/10 . . . . . . simplify
x' = 5/10 = 1/2 . . . . divide by 7
Using the first equation to find y', we have ...
y' = 3x' -13/10 = 3(5/10) -13/10 = 2/10 = 1/5
So, the solution is ...
x = 1/x' = 1/(1/2) = 2
y = 1/y' = 1/(1/5) = 5
(x, y) = (2, 5)
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The attached graph shows the original equations. There are two points of intersection of the curves, one at (0, 0). Of course, both equations are undefined at that point, so each graph will have a "hole" there.
Answer:
X= -10
Step-by-step explanation:
The x coordinate is halfway between 2 and 10 = 2 + (10-2)/2 = 2+4 = 6
so midpoint is C (6,3)
Answer:
120x^3y^7
We can use the Pascal's triangle to solve this question.
This pascal's triangle is shown in the Image below. To build the triangle, begin with the number 1 at the top, then continue placing numbers below it in a triangular pattern. In this way, each number are the numbers directly above added together. So, the expression is :
(x+y)10
After you do the steps you be left with:
120x^3y^7
15 seconds= 6.66..
45+15=60
20+6.66=26.66 beats in a minute
I think. This might be wrong but that’s how I would do it