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Ganezh [65]
3 years ago
9

A boat starts in Wilmington and sails 5 miles due east and then 3 miles due south. What is the approximate shortest distance bac

k to Wilmington?
Mathematics
1 answer:
GarryVolchara [31]3 years ago
7 0

Answer:

I would say approximately 5.8 miles

Step-by-step explanation:

(This answer may be wrong)

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Which polynomial is a perfect square trinomial? (4 points) 9x2 − 12x + 4 36b2 − 24b + 16 16x2 − 24x − 9 4a2 − 10a − 25ynomial is
o-na [289]

Answer:

9x² − 12x + 4

Step-by-step explanation:

A perfect square trinomial:

a² + 2ab +b²= (a + b)²

a² - 2ab +b²= (a - b)²

9x² − 12x + 4 = (3x)² - 2*(3x)*2 + 2² = (3x - 2)²

36b² − 24b + 16

16x² − 24x − 9

4a² − 10a − 25

8 0
3 years ago
Read 2 more answers
Evaluate the expressions when x = 10 &amp; y =8.<br><br> 2y
klasskru [66]

Answer: 64

Step-by-step explanation:

y=8

plug in 8 for y

2(8)=64

5 0
3 years ago
50 POINTS
Tcecarenko [31]

Answer:

<u>Part 1: C. $3,159.30</u>

<u>Part 2. C. –5; –135; –10,935</u>

Step-by-step explanation:

Part 1:

Price of the boat = $ 16,600

Depreciation rate = 14% = 0.14

Time of utilization of the boat = 11 years

Price of the boat after 11 years = Original price * (1 - Depreciation rate)^Time of utilization of the boat

Price of the boat after 11 years = 16,600 * (1 - 0.14)¹¹

Price of the boat after 11 years = 16,600 * 0.1903

<u>Price of the boat after 11 years = $ 3,159.30</u>

Part 2:

Let's find out the first term of the sequence given:

A(1) = -5 * 3¹⁻¹

A(1) = -5 * 1

A(1) = -5

Let's find out the fourth term of the sequence given:

A(4) = -5 * 3⁴⁻¹

A(4) = -5 * 3³

A(4) = -5 * 27

A(4) = -135

Let's find out the eighth term of the sequence given:

A(8) = -5 * 3⁸⁻¹

A(8) = -5 * 3⁷

A(8) = -5 * 2,187

A(8) = -10,935

4 0
3 years ago
Let ​f(x)equals=33xminus−​1, ​h(x)equals=startfraction 7 over x plus 5 endfraction 7 x+5 . find ​(hcircle◦​f)(66​).
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\bf \begin{cases}&#10;f(x)=3x-1\\&#10;h(x)=\cfrac{7}{x+5}\\\\&#10;(h\circ f)(x)=h(~~f(x)~~)&#10;\end{cases}&#10;\\\\\\&#10;f(66)=3(66)-1\implies \boxed{f(66)=197}&#10;\\\\\\&#10;\stackrel{h(~~f(x)~~)}{h(~~f(66)~~)}\implies \stackrel{h(~~f(66)~~)}{h\left(~~\boxed{197}~~ \right)}=\cfrac{7}{\boxed{197}+5}\implies h\left(~~\boxed{197}~~ \right)=\cfrac{7}{202}
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3 years ago
PLEASE HELP ASAP THANK YOU
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1-85.71% of the team attendance
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