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Lera25 [3.4K]
3 years ago
12

A circle has a radius of 13 inches. Which equation can be used to find the diameter of this circle?d=2π(13)

Mathematics
2 answers:
sladkih [1.3K]3 years ago
6 0
Diameter is twice of a radius
d=2r
r=13 inches given

d=2*13
motikmotik3 years ago
6 0

Answer:  d=2(13)

Step-by-step explanation:

We know that, the diameter of a circle is twice of the radius of the circle.

Therefore, if r is the radius of the circle, then diameter of the circle will be :-

d=2r

Given: A circle has a radius of 13 inches.

Therefore, the diameter of the given circle will be :-

d=2(13)=26\ inches

Hence, the equation which can be used to find the diameter of this circle is d=2(13)

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Alex

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D. y-4= -3/2(x+5)

Step-by-step explanation:

Firstly, taking two valid ordered pairs from the graph:

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When completing the square on the equation c2 + 110 = 12, the resulting solution is:<br> It
Delvig [45]

Answer:

c=1 and c=-12

Step-by-step explanation:

The correct equation is:

c^2+11c=12

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We have:

c^2+11c=12

In order to solve by completing the square method we will carry out the following operations to the given equation to get a perfect square binomial.

We can write as:

c^2+2.\frac{11}{2}c=12  

c^2+2.\frac{11}{2}c+(\frac{11}{2})^2-(\frac{11}{2})^2=12

(c+\frac{11}{2})^2-(\frac{11}{2})^2=12  [As  c^2+2.\frac{11}{2}c+(\frac{11}{2})^2=(c+\frac{11}{2})^2]

Adding both sides by (\frac{11}{2})^2

(c+\frac{11}{2})^2-(\frac{11}{2})^2+(\frac{11}{2})^2=12+(\frac{11}{2})^2

(c+\frac{11}{2})^2=12+\frac{121}{4}  

Taking LCD to add fraction.

(c+\frac{11}{2})^2=\frac{48}{4}+\frac{121}{4}

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Taking square root both sides.

\sqrt{(c+\frac{11}{2})^2}=\sqrt{\frac{169}{4}}

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Subtracting both sides by \frac{11}{2} :

c+\frac{11}{2}-\frac{11}{2}=\pm\frac{13}{2}-\frac{11}{2}

c=\pm\frac{13}{2}-\frac{11}{2}

So, we have:

c=\frac{13}{2}-\frac{11}{2} and c=-\frac{13}{2}-\frac{11}{2}

c=\frac{2}{2} and c=\frac{-24}{2}

c=1 and c=-12  (Answer)

6 0
4 years ago
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