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Svet_ta [14]
3 years ago
15

5. You are scheduling your classes for next year. There are 4 required classes: a physical education

Mathematics
1 answer:
puteri [66]3 years ago
5 0
<h3>Answer:   450</h3>

==============================================

Explanation:

For now, let's consider we can only select 2 classes instead of 4. Let's say we only had to worry about PE and history.

Let A,B,C,D,E represent the five PE classes.

Let F,G,H,I,J,K represent the six history classes.

If you arrange the letters in a table, you should get 5*6 = 30 different inner boxes of the table. Refer to the diagram below.

Each two letter code in the table represents the 2 class combo. For example, BG means you picked PE class B and history class G.

This idea can be extend to selecting 3 classes. Imagine that each of the codes in the table are laid along the side of a new table. So we'd have a table of 30 rows. Then lay out 5 columns (say with letters L,M,N,O,P) to represent the 5 English classes. You would get a table of 30*5 = 150 different combos here. Of course you shouldn't actually make such a table since it's so large, but I'm simply just saying for you to imagine one. All of the tables mentioned are completely optional. A tree diagram is another way to organize things, though tree diagrams tend to get cumbersome.

Anyway, we would have 5*6*5 = 30*5 = 150 different ways to pick the PE, history and English classes. We can extend this out to include the math classes as well.

-------------------------

In short, all we do is multiply the given values together:

5*6*5*3 = 30*15 = 450

This idea is known as the counting principle.

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Answer:

If the reindeer do not fight, there are 5!=120 ways to line them up in a straight line.

Out of these, Bloopin and Rudy are together in 4!=24 times.  Similarly Rudy and Bloopin will be together 4!=24 times.  So the number of ways they are not together is 120-24-24=72 ways.

Hope this helps.    :)

Step-by-step explanation:

Spanish:

Si los renos no luchan, hay 5! = 120 formas de alinearlos en línea recta.

De estos, Bloopin y Rudy están juntos en 4! = 24 veces. De manera similar, Rudy y Bloopin estarán juntos 4! = 24 veces. Entonces, el número de formas en que no están juntas es 120-24-24 = 72 formas.

Espero que esto ayude       :)

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